Question

Найти массу ртути о объем кислорода, которые образовались при разложении 50 г оксида ртути

Answer 1

50г         хг       хл
2HgO = 2Hg + O2

50г:433,2г/моль=хг:401,2
х=50*401,2:433,2=46,3-масса ртути
50г:433,2г/моль = хл:22,4л/моль
х=50*22,4:433,2=1,03л

Answer 2

Calculating the Mass of Mercury and the Volume of Oxygen

To find the mass of mercury and the volume of oxygen formed during the decomposition of 50g of mercury oxide, we can use stoichiometry to calculate the quantities involved.

Step 1: Write the Balanced Chemical Equation The decomposition of mercury(II) oxide can be represented by the following balanced chemical equation: ``` 2HgO(s) -> 2Hg(l) + O2(g) ``` This equation shows that 2 moles of mercury(II) oxide decompose to produce 2 moles of mercury and 1 mole of oxygen.

Step 2: Calculate the Moles of Mercury(II) Oxide Given mass of mercury oxide = 50g Molar mass of HgO = 200.59 g/mol Moles of HgO = Given mass / Molar mass Moles of HgO = 50g / 200.59 g/mol Moles of HgO = 0.2493 mol

Step 3: Use Stoichiometry to Calculate the Moles of Mercury and Oxygen From the balanced chemical equation, we know that 2 moles of HgO produce 2 moles of Hg and 1 mole of O2. So, moles of Hg = 2 * moles of HgO Moles of Hg = 2 * 0.2493 mol = 0.4986 mol Moles of O2 = 1 * moles of HgO Moles of O2 = 1 * 0.2493 mol = 0.2493 mol

Step 4: Calculate the Mass of Mercury and the Volume of Oxygen Now, we can calculate the mass of mercury and the volume of oxygen produced. - Mass of mercury = Moles of Hg * Molar mass of Hg - Volume of oxygen = Moles of O2 * molar volume of gas at STP

Step 5: Perform the Calculations - Mass of mercury = 0.4986 mol * 200.59 g/mol = 100g - Volume of oxygen = 0.2493 mol * 22.4 L/mol = 5.58L

Conclusion The mass of mercury formed during the decomposition of 50g of mercury oxide is 100g, and the volume of oxygen formed is 5.58L.