Question

При горении пропана образовалось 3 моля углекислого газа.Определить исходный объем пропана.

Answer 1

      х                       3моль

C3H8 + 5O2 = 3CO2  + 4H2O

1 моль                 3 моль

 

х=3 моль

объем = 3*22,4=67,2л

Answer 2

Calculating the Initial Volume of Propane

To calculate the initial volume of propane, we can use the balanced chemical equation for the combustion of propane and the ideal gas law.

The balanced chemical equation for the combustion of propane is: C3H8 + 5O2 → 3CO2 + 4H2O

From the equation, we can see that 1 mole of propane (C3H8) produces 3 moles of carbon dioxide (CO2) when it burns.

Given that 3 moles of carbon dioxide were produced, we can use this information to calculate the initial volume of propane.

Using the ideal gas law equation: PV = nRT

Where: - P = pressure - V = volume - n = number of moles - R = ideal gas constant - T = temperature

We can rearrange the equation to solve for volume: V = (nRT) / P

Given: - n = 3 moles (number of moles of carbon dioxide produced) - R = ideal gas constant (0.0821 L·atm/mol·K) - T = temperature (assumed to be constant) - P = pressure (assumed to be constant)

We can calculate the initial volume of propane using the above information.

Calculation

Using the ideal gas law equation: V = (nRT) / P

Substituting the given values: V = (3 moles * 0.0821 L·atm/mol·K * T) / P

Since the temperature and pressure are not provided, we cannot calculate the exact initial volume of propane without this information.

If you have the temperature and pressure values, please provide them, and I can help you calculate the initial volume of propane.