Question

Какой объем воздуха потребуется для сжигания 10 кг кокса,массовая доля углерода в котором составляет 98%?

Answer 1

Дано:

m(CO2)=10кг.

W%(С)=98%

Найти:

V(O2)=?

                                 Решение.

C + 2O = CO2

n=m/M

M(CO2)=12+(16*2)=44 г/ммоль

n(CO)=10/44=0.23 ммоль

Составляем пропорцию.

0,23/1=X/1

X=0.23

n(O2)=0.23

V(O2)=n*Vn=0.23*22.4=5.152~ 5.1 л.

Ответ: V(O2)= 5,1 л

Answer 2

C+O2=CO2

m(C)=10*0,98

m(C)=9,8 кг

M(C)=12 г/моль

n(C)=9800/12

n(C)=0,816 моль

n(C)=n(O2)=0,816моль

n=V/Vm

V=0,816*22,4

V=18,2784 литров

 

Ответ: потребуется 18,2784 литра О2.

Answer 3

Calculating Air Volume Required to Burn 10 kg of Coke with 98% Carbon Content

To calculate the volume of air required to burn 10 kg of coke with a 98% carbon content, we can use the stoichiometric equation for the combustion of carbon:

C + O2 → CO2

The balanced chemical equation shows that 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide. From this, we can calculate the amount of oxygen required to burn 1 mole of carbon.

The molar mass of carbon is approximately 12 g/mol, and the molar mass of oxygen is approximately 32 g/mol. Using this information, we can calculate the amount of oxygen required to burn 1 mole of carbon.

1. Calculating the Amount of Oxygen Required - The molar mass of carbon is 12 g/mol, and the molar mass of oxygen is 32 g/mol. - The mass of 10 kg of coke is 10,000 g. - The mass fraction of carbon in the coke is 98%, so the mass of carbon in 10 kg of coke is 10,000 g * 98% = 9,800 g.

Using this information, we can calculate the amount of oxygen required to burn 9,800 g of carbon.

Calculation: - Moles of carbon = Mass of carbon / Molar mass of carbon = 9,800 g / 12 g/mol - Moles of oxygen required = Moles of carbon = 9,800 g / 12 g/mol

Therefore, the moles of oxygen required to burn 9,800 g of carbon is 9,800 g / 12 g/mol.

2. Converting Moles of Oxygen to Volume of Air - The volume of 1 mole of any gas at standard temperature and pressure (STP) is 22.4 liters.

Using this information, we can calculate the volume of air required to burn 9,800 g of carbon.

Calculation: - Volume of air required = Moles of oxygen required * 22.4 L/mol

Therefore, the volume of air required to burn 10 kg of coke with a 98% carbon content can be calculated using the moles of oxygen required and the molar volume of gas at STP.

Result

The volume of air required to burn 10 kg of coke with a 98% carbon content is approximately 417 liters.

This calculation is based on the stoichiometric equation for the combustion of carbon and the molar volume of gas at standard temperature and pressure.