Question

Көлемі 30 м куб күкірт(4) оксиді тотығу үшін қанша көлем ауа қажет?

Answer 1

Осылай сияқты:) Сәттілік!

Answer 2

Calculating the Volume of Air Needed for the Oxidation of 30 m³ of Carbon Monoxide (CO)

To calculate the volume of air needed for the oxidation of 30 m³ of carbon monoxide (CO) to carbon dioxide (CO2), we can use the balanced chemical equation for the reaction:

2CO + O2 → 2CO2

From the balanced equation, we can see that 1 mole of CO reacts with 0.5 moles of O2. Therefore, to calculate the volume of air needed, we can use the molar volume of a gas at standard temperature and pressure (STP), which is approximately 22.4 liters per mole.

Calculation

Given: - Volume of CO (V_CO) = 30 m³ - Molar ratio of CO to O2 = 1:0.5

Using the molar volume of a gas at STP, we can calculate the volume of air needed as follows:

1. Convert the volume of CO from cubic meters to liters: - V_CO = 30 m³ * 1000 = 30,000 liters

2. Calculate the moles of CO: - Moles of CO = V_CO / molar volume at STP = 30,000 / 22.4 ≈ 1339.29 moles

3. Calculate the moles of O2 needed: - Moles of O2 = Moles of CO * 0.5 = 1339.29 * 0.5 = 669.65 moles

4. Convert the moles of O2 to volume at STP: - Volume of O2 = Moles of O2 * molar volume at STP = 669.65 * 22.4 ≈ 14,991.16 liters

Therefore, approximately 14,991.16 liters of air are needed for the oxidation of 30 m³ of carbon monoxide to carbon dioxide.

(#1)