Question

Напишите ионное уравнение которое происходит между веществами CuCl2 SnO H2SO4

Answer 1

Cu2 + +2 Cl-+2 H + +SO42-= Cu2 + +SO42-+2 H + +2 Cl- 

Answer 2

Ionic Equation for the Reaction between CuCl2, SnO, and H2SO4

The ionic equation for the reaction between CuCl2, SnO, and H2SO4 can be represented as follows:

CuCl2 + SnO + H2SO4 →

First, let's break down the individual components of the reaction:

1. CuCl2: - Copper(II) chloride, also known as cupric chloride, is a chemical compound with the formula CuCl2. - It dissociates in water to form copper(II) ions (Cu^2+) and chloride ions (Cl^-).

2. SnO: - Tin(II) oxide, also known as stannous oxide, is a chemical compound with the formula SnO. - It can react with acids to form tin(II) salts and water.

3. H2SO4: - Sulfuric acid, with the formula H2SO4, is a strong mineral acid. - It dissociates in water to form hydrogen ions (H^+) and sulfate ions (SO4^2-).

Now, let's write the ionic equation for the reaction:

CuCl2 + SnO + H2SO4 → Cu^2+ + 2Cl^- + Sn^2+ + 2OH^- + 2H^+ + SO4^2-

In this equation, Cu^2+ and Cl^- are the ions from CuCl2, Sn^2+ and OH^- are the ions from SnO, and H^+ and SO4^2- are the ions from H2SO4.

This ionic equation represents the dissociation of the compounds into their respective ions and the subsequent recombination to form new compounds.

If you have any further questions or need additional information, feel free to ask!