Question

ПОМОГИТЕ!!!!!!!!!1Найти количество молекул воды образующейся при взрыве смеси 20 г водорода с кислородом.

Answer 1

Решение смотри во вложении. Должно быть понятно. Перекликается с предыдущей задачкой )) 

Под чертой решение Вашей задачи. А уравнение реакции подходит для этой задачи. Надо списать само уравнение реакции, а потом решение под чертой.

Answer 2

Calculation of the Number of Water Molecules Formed

To calculate the number of water molecules formed during the explosion of a mixture of 20 grams of hydrogen with oxygen, we need to use the concept of molar mass and Avogadro's number.

1. Calculate the number of moles of hydrogen: - The molar mass of hydrogen (H₂) is approximately 2 grams/mol. - Divide the mass of hydrogen (20 grams) by the molar mass of hydrogen to get the number of moles of hydrogen: 20 grams / 2 grams/mol = 10 moles of hydrogen.

2. Calculate the number of moles of oxygen: - The molar mass of oxygen (O₂) is approximately 32 grams/mol. - Since the ratio of hydrogen to oxygen in water is 2:1, the number of moles of oxygen is half the number of moles of hydrogen: 10 moles of hydrogen / 2 = 5 moles of oxygen.

3. Calculate the limiting reactant: - The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product that can be formed. - In this case, since the ratio of hydrogen to oxygen in water is 2:1, the limiting reactant is oxygen because there are fewer moles of oxygen (5 moles) compared to hydrogen (10 moles).

4. Calculate the number of moles of water formed: - Since the ratio of hydrogen to water is 2:1, the number of moles of water formed is equal to the number of moles of oxygen: 5 moles of water.

5. Calculate the number of water molecules: - Avogadro's number states that there are approximately 6.022 x 10^23 molecules in one mole of a substance. - Multiply the number of moles of water formed by Avogadro's number to get the number of water molecules: **5 moles of water x 6.022 x 10^23