Question

Рассчитать число структурных частиц в 44,8 л кислород

Answer 1

N(O2) = 44.8 л/22,4 л/моль = 2 моль
N = 2 моль×6,02×10²³молекул/моль = 1,204×10²⁴ молекул
Число атомов будет вдвое больше, так как молекула кислорода состоит из двух атомов:
N = 1,204×10²⁴ молекул×2 атомов/молекул=2,408×10²⁴ атомов

Answer 2

Calculation of the Number of Structural Particles in 44.8 liters of Oxygen

To calculate the number of structural particles in 44.8 liters of oxygen, we need to determine the number of moles of oxygen and then convert it to the number of structural particles.

The molar mass of oxygen (O₂) is approximately 32 g/mol To calculate the number of moles of oxygen, we can use the formula:

Number of moles = Mass / Molar mass

Given that we have 44.8 liters of oxygen, we need to convert it to grams using the density of oxygen. The density of oxygen at standard conditions is approximately 1.43 g/L Therefore, the mass of oxygen can be calculated as:

Mass = Volume × Density

Substituting the values, we have:

Mass = 44.8 L × 1.43 g/L

Now, we can calculate the number of moles of oxygen:

Number of moles = Mass / Molar mass

Let's calculate it step by step:

Step 1: Calculate the mass of oxygen:

Mass = 44.8 L × 1.43 g/L = 64.064 g

Step 2: Calculate the number of moles of oxygen:

Number of moles = Mass / Molar mass = 64.064 g / 32 g/mol = 2 moles

Now that we have the number of moles of oxygen, we can convert it to the number of structural particles. One mole of any substance contains Avogadro's number (6.022 × 10^23) of structural particles Therefore, the number of structural particles in 2 moles of oxygen is:

Number of structural particles = Number of moles × Avogadro's number

Number of structural particles = 2 moles × 6.022 × 10^23 particles/mol

Let's calculate it:

Number of structural particles = 2 × 6.022 × 10^23 particles/mol = 1.2044 × 10^24 particles

Therefore, there are approximately 1.2044 × 10^24 structural particles in 44.8 liters of oxygen.

Please note that this calculation assumes that the oxygen is in its standard state and behaves ideally.