Question

Ребята, спасайте! :) Приведите электродные реакции, происходящие при электролизе расплава бромида свинца с инертными элеектродами

Answer 1

Катод: Pb(2+)+2e --> Pb
Анод: 2Br(-) - 2e --> Br2
Суммарно:
PbBr2 ------> Pb+Br2

Answer 2

Electrolysis of Lead Bromide

The electrolysis of lead bromide involves the use of inert electrodes to separate the lead and bromine from the compound. Here are the electrode reactions that occur during the electrolysis:

1. At the Anode (Positive Electrode): - At the anode, bromide ions are oxidized to form bromine gas and release electrons. - The half-reaction at the anode is: ``` 2Br⁻(l) → Br2(g) + 2e⁻ ``` - This reaction occurs because the anode attracts negatively charged ions, and in this case, bromide ions are oxidized to form bromine gas.

2. At the Cathode (Negative Electrode): - At the cathode, lead ions are reduced to form lead metal and gain electrons. - The half-reaction at the cathode is: ``` Pb²⁺(l) + 2e⁻ → Pb(l) ``` - This reaction occurs because the cathode attracts positively charged ions, and in this case, lead ions are reduced to form lead metal.

These electrode reactions illustrate the process of electrolysis of lead bromide, where lead metal is deposited at the cathode, and bromine gas is produced at the anode.