Question

Al+H2SO4=Al2(SO4)3+H2 Составить электронный баланс

Answer 1

$Al^0+H_2^{+1}S^{+6}O_4^{-2}=Al_2^{+3}(S^{+6}O_4^{-2})_3+H_2^0\\Al^0-3e=Al^{+3}|\ |2\\2H^{+1}+2e=H_2^0|6|3\\\\2Al+3H_2SO_4=Al_2(SO_4)_3+3H_2$

Answer 2

Electron Balance for the Reaction: Al + H2SO4 = Al2(SO4)3 + H2

To balance the electron transfer in the reaction between aluminum (Al) and sulfuric acid (H2SO4) to form aluminum sulfate (Al2(SO4)3) and hydrogen gas (H2), we need to consider the oxidation states of the elements involved.

The oxidation state of aluminum (Al) is +3, and the oxidation state of hydrogen (H) is +1. The oxidation state of sulfur (S) in sulfuric acid (H2SO4) is +6, and the oxidation state of oxygen (O) is -2.

The balanced equation for the reaction is as follows:

2 Al + 3 H2SO4 → Al2(SO4)3 + 3 H2

In this balanced equation, the number of atoms and the charge on both sides of the equation are equal, indicating that the reaction is balanced both in terms of mass and charge.

Please note that the electron balance is not explicitly mentioned in the search results, but the balanced equation provided above ensures that the reaction is balanced in terms of both atoms and charge.