Question

Какой объем хлороводорода выделится при взаимодействии 10 литров водорода с хлором

Answer 1

H2+CL2=2HCL
V(HCL)=2V(H2)= 2*10л = 20л

Answer 2

Reaction Equation and Molar Volumes

When 10 liters of hydrogen gas react with chlorine gas, the following reaction occurs: H2 + Cl2 → 2HCl

According to Avogadro's law, at the same temperature and pressure, equal volumes of gases contain an equal number of molecules. Therefore, 1 mole of any gas occupies the same volume as 1 mole of any other gas at the same temperature and pressure.

The molar volume of any gas at standard temperature and pressure (STP) is approximately 22.4 liters.

Calculation

Given that 10 liters of hydrogen gas react with chlorine, we can calculate the volume of hydrogen chloride gas produced using the stoichiometry of the reaction.

From the balanced chemical equation, we can see that 1 mole of hydrogen gas reacts with 1 mole of chlorine gas to produce 2 moles of hydrogen chloride gas.

Using the molar volume of gases at STP, we can calculate the volume of hydrogen chloride gas produced.

Volume of Hydrogen Chloride Gas Produced

Using the molar volume of gases at STP, the volume of hydrogen chloride gas produced can be calculated as follows:

1. The number of moles of hydrogen gas = Volume of hydrogen gas / Molar volume of gases at STP 2. The number of moles of hydrogen chloride gas produced = 2 * (number of moles of hydrogen gas) 3. Volume of hydrogen chloride gas produced = (number of moles of hydrogen chloride gas produced) * Molar volume of gases at STP

Result

The volume of hydrogen chloride gas produced when 10 liters of hydrogen gas react with chlorine gas is approximately 44.8 liters.

Note: The actual volume may vary slightly due to factors such as non-ideal behavior of gases and deviations from STP conditions.