Question

при гидролизе жира трипальметина количеством вещества 7 моль был получен глицерин массойА.8,44г Б.64.4г В.644г Г.222г

Answer 1

при гидролизе жира трипальметина количеством вещества 7 моль был получен глицерин массой В.644г

Answer 2

Hydrolysis of Tri-palmitin and Glycerin Production

When 7 moles of tri-palmitin undergo hydrolysis, the amount of glycerin produced can be calculated using the molar mass of tri-palmitin and the stoichiometry of the reaction.

The molar mass of tri-palmitin (C51H98O6) can be calculated as follows: - Carbon (C) has a molar mass of approximately 12.01 g/mol. - Hydrogen (H) has a molar mass of approximately 1.008 g/mol. - Oxygen (O) has a molar mass of approximately 16.00 g/mol.

Using these values, the molar mass of tri-palmitin can be calculated as: \[ 51 \times 12.01 + 98 \times 1.008 + 6 \times 16.00 \]

Let's calculate the molar mass of tri-palmitin first.

Molar mass of tri-palmitin: \[ 51 \times 12.01 + 98 \times 1.008 + 6 \times 16.00 = 807.52 \, \text{g/mol} \]

Now, let's calculate the mass of glycerin produced when 7 moles of tri-palmitin undergo hydrolysis.

Mass of glycerin produced: \[ 7 \, \text{moles} \times 3 \times \text{molar mass of glycerin} \]

The molar mass of glycerin (C3H8O3) can be calculated as: \[ 3 \times 12.01 + 8 \times 1.008 + 3 \times 16.00 \]

Let's calculate the molar mass of glycerin.

Molar mass of glycerin: \[ 3 \times 12.01 + 8 \times 1.008 + 3 \times 16.00 = 92.09 \, \text{g/mol} \]

Now, let's calculate the mass of glycerin produced.

Mass of glycerin produced: \[ 7 \, \text{moles} \times 3 \times 92.09 \, \text{g/mol} = 1938.63 \, \text{g} \]

Therefore, the correct answer is В. 644 г.