Question

Расчитайте малекулярные массы для веществ:CaCO3 FeSO4 Fe2CSO4 AECE3

Answer 1

1. М(FeSO4)=5640+12+48=110 г\моль
M(Ca)=40  г\моль
M(S)=12  г\моль
M(O)=16*3=48  г\моль
2.M(FeSO4)=56+32+64=152  г\моль
M(Fe)=56  г\моль
M(S)=32  г\моль
M(O)=16*4=64  г\моль
3. M(Fe2CSO4)=112+12+32+64=220  г\моль
M(Fe)=56*2=112  г\моль
M(C)=12  г\моль
M(S)=32  г\моль
M(O)=16*4=64  г\моль

Answer 2

Molecular Mass Calculation for Substances

To calculate the molecular mass of a substance, we need to consider the atomic masses of the elements present in the compound and their respective stoichiometric coefficients. Here are the molecular masses for the substances you mentioned:

1. CaCO3 (Calcium Carbonate): - Calcium (Ca) atomic mass: 40.08 g/mol - Carbon (C) atomic mass: 12.01 g/mol - Oxygen (O) atomic mass: 16.00 g/mol - Molecular mass of CaCO3 = (1 * Ca) + (1 * C) + (3 * O) = 40.08 + 12.01 + (3 * 16.00) = 100.09 g/mol [[1]].

2. FeSO4 (Iron(II) Sulfate): - Iron (Fe) atomic mass: 55.85 g/mol - Sulfur (S) atomic mass: 32.07 g/mol - Oxygen (O) atomic mass: 16.00 g/mol - Molecular mass of FeSO4 = (1 * Fe) + (1 * S) + (4 * O) = 55.85 + 32.07 + (4 * 16.00) = 151.91 g/mol [[2]].

3. Fe2(SO4)3 (Iron(III) Sulfate): - Iron (Fe) atomic mass: 55.85 g/mol - Sulfur (S) atomic mass: 32.07 g/mol - Oxygen (O) atomic mass: 16.00 g/mol - Molecular mass of Fe2(SO4)3 = (2 * Fe) + (3 * S) + (12 * O) = (2 * 55.85) + (3 * 32.07) + (12 * 16.00) = 399.88 g/mol [[3]].

4. AECE3 (Unknown Substance): Unfortunately, I couldn't find any information about the substance AECE3. It is possible that it may be a specific compound or a chemical formula that is not widely known. If you have any additional information about AECE3, I can try to assist you further.

Please note that the molecular masses provided above are based on the atomic masses of the elements as of the current understanding in chemistry.