Question

Для каждой реакции укажите, какое вещество является окислителем, какое восстановителем, какое восстанавливается?Bi + HNO3(разб) → Bi(NO3)2 + NO + H2OH2SO3 + Cl2 + H2O → H2SO4 + HClS + KOH → K2S + K2SO4 + H2OH2S + Cl2 + H2O → H2SO4 + HCl

Answer 1

Bi + HNO3(разб) → Bi(NO3)2 + NO + H2O

Bi  - восстановитель, HNO3 - окислитель, он восстанавливается.

 

H2SO3 + Cl2 + H2O → H2SO4 + HCl

H2SO3 - восстановитель, Cl2 - окислитель, он восстанавливается.

 

S + KOH → K2S + K2SO4 + H2O

Это реакция диспропорционирования, поэтому тут и окислителем и восстановителем является сера, она и окисляется и восстанавливается.

 

H2S + Cl2 + H2O → H2SO4 + HCl

H2S - восстановитель, Cl2 - окислитель, он восстанавливается.

Answer 2

Reaction 1: Bi + HNO3 (разб) → Bi(NO3)2 + NO + H2O

In this reaction, the substance Bi is being oxidized, HNO3 is acting as the oxidizing agent (or the oxidizer), and Bi(NO3)2 is being reduced. The reaction can be represented as follows:

Bi + HNO3 (разб) → Bi(NO3)2 + NO + H2O

- Oxidizing agent: HNO3 - Reducing agent: Bi - Substance being reduced: Bi(NO3)2

Reaction 2: H2SO3 + Cl2 + H2O → H2SO4 + HCl

In this reaction, H2SO3 is being oxidized, Cl2 is acting as the oxidizing agent, and H2SO4 is being reduced. The reaction can be represented as follows:

H2SO3 + Cl2 + H2O → H2SO4 + HCl

- Oxidizing agent: Cl2 - Reducing agent: H2SO3 - Substance being reduced: H2SO4

Reaction 3: S + KOH → K2S + K2SO4 + H2O

In this reaction, S is being oxidized, KOH is acting as the oxidizing agent, and K2S is being reduced. The reaction can be represented as follows:

S + KOH → K2S + K2SO4 + H2O

- Oxidizing agent: KOH - Reducing agent: S - Substance being reduced: K2S

Reaction 4: H2S + Cl2 + H2O → H2SO4 + HCl

In this reaction, H2S is being oxidized, Cl2 is acting as the oxidizing agent, and H2SO4 is being reduced. The reaction can be represented as follows:

H2S + Cl2 + H2O → H2SO4 + HCl

- Oxidizing agent: Cl2 - Reducing agent: H2S - Substance being reduced: H2SO4

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