Question

Определите, атомы какого элемента окисляются, а какого - восстанавливаются в следующих реакциях:1)2KBr+CL2=2KCL+Br22)Mg+2HCL=MgCL2+H2^Укажите, какие вещества в этих реакциях играют роль восстановителей, а какие окислителей.

Answer 1

1)KBr-восстановитель,Cl2-окислитель.Br восстанавливается,Cl окисляется
2)Mg-восстановитель,HCl-окислитель.Mg восстанавливается,H+ окисляется

Answer 2

Atoms that are oxidized and reduced in the given reactions:

1) In the reaction 2KBr + Cl2 = 2KCl + Br2, the atoms of bromine (Br) are oxidized, while the atoms of chlorine (Cl) are reduced.

2) In the reaction Mg + 2HCl = MgCl2 + H2, the atoms of magnesium (Mg) are oxidized, while the atoms of hydrogen (H) are reduced.

Role of substances as oxidizing agents and reducing agents:

1) In the reaction 2KBr + Cl2 = 2KCl + Br2, chlorine (Cl2) acts as the oxidizing agent, as it accepts electrons from the bromine atoms, causing them to be oxidized. The bromine atoms lose electrons and their oxidation state increases from -1 to 0, forming bromine molecules (Br2). Therefore, bromine (Br) acts as the reducing agent.

2) In the reaction Mg + 2HCl = MgCl2 + H2, hydrochloric acid (HCl) acts as the oxidizing agent, as it accepts electrons from the magnesium atoms, causing them to be oxidized. The magnesium atoms lose electrons and their oxidation state increases from 0 to +2, forming magnesium chloride (MgCl2). Therefore, magnesium (Mg) acts as the reducing agent.

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