Вопрос задан 27.04.2019 в 08:08. Предмет Химия. Спрашивает Руденко Сева.

Визначте молекулярну формулу вуглеводню, якщо внаслідок спалювання 1,12 г цього вуглеводню

утворилося 1,792 л вуглекислого газу (н.у.) і 1,44 г води, а відносна густина його за гелієм дорівнює 28.
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Отвечает Ситников Миша.

 Общаться в чатеn(CO2)=1.792/22.4=0.08 n©=0.08 m©= 0.08*12=0.96гn(H2O)=1.44/18=0.08 n(H)=0.16 m(H)=1.16г0.96+1.16=1.12гC:H=0.08:0.16  или     8:16M= 28*4=112г/мольОтвет: С8Н16
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Molecular Formula of the Hydrocarbon

To determine the molecular formula of the hydrocarbon, we need to analyze the products of its combustion. According to the information provided, 1.12 g of the hydrocarbon produced 1.792 L of carbon dioxide (at standard temperature and pressure) and 1.44 g of water. Additionally, the relative density of the hydrocarbon with respect to helium is given as 28.

To find the molecular formula, we can follow these steps:

1. Calculate the number of moles of carbon dioxide produced: - The molar mass of carbon dioxide (CO2) is 44.01 g/mol. - Using the given volume of 1.792 L, we can convert it to moles using the ideal gas law: PV = nRT. - Assuming standard temperature and pressure (STP), the value of R is 0.0821 L·atm/(mol·K). - Plugging in the values, we get: (1 atm) * (1.792 L) = n * (0.0821 L·atm/(mol·K)) * (273.15 K). - Solving for n, we find that the number of moles of carbon dioxide is approximately 0.081 mol.

2. Calculate the number of moles of water produced: - The molar mass of water (H2O) is 18.02 g/mol. - Using the given mass of 1.44 g, we can convert it to moles: 1.44 g / 18.02 g/mol ≈ 0.08 mol.

3. Determine the empirical formula: - The empirical formula represents the simplest whole number ratio of atoms in a compound. - To find the empirical formula, we need to determine the ratio of carbon to hydrogen in the hydrocarbon. - From the combustion reaction, we know that the carbon in the hydrocarbon is converted to carbon dioxide, and the hydrogen is converted to water. - The ratio of carbon to hydrogen can be found by dividing the number of moles of carbon dioxide by the number of moles of water: 0.081 mol CO2 / 0.08 mol H2O ≈ 1.01. - This ratio suggests that there is approximately 1 carbon atom for every 1 hydrogen atom in the hydrocarbon.

4. Determine the molecular formula: - To find the molecular formula, we need to know the molar mass of the hydrocarbon. - The relative density of the hydrocarbon with respect to helium is given as 28. - The molar mass of helium is approximately 4 g/mol. - The relative density is the ratio of the molar mass of the hydrocarbon to the molar mass of helium: 28 = Molar mass of hydrocarbon / 4. - Solving for the molar mass of the hydrocarbon, we find that it is approximately 112 g/mol.

- Since the empirical formula indicates a 1:1 ratio of carbon to hydrogen, and the molar mass of the hydrocarbon is approximately 112 g/mol, we can conclude that the molecular formula of the hydrocarbon is C4H4.

Please note that the search results provided by You.com did not contain relevant information for this specific question. The answer provided above is based on the principles of stoichiometry and molar mass calculations.

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