Question

Помогите!Запишите уравнение реакций,протекающих на воздухе с литием,лишённым вазелиновой защиты.1)Li+O2----->2)Li+N2------>3)Li+H2o------>4)Li2O+Co2----->Две первые реакции рассмотрите с позицией окисления-восстановления1)....2)....

Answer 1

 Li + O2 -----> LiO2 

Answer 2

Equation 1: Li + O2 → ?

The reaction between lithium (Li) and oxygen (O2) in the presence of air can be represented by the equation: 2Li + O2 → 2LiO [[1]]

Equation 2: Li + N2 → ?

The reaction between lithium (Li) and nitrogen (N2) in the presence of air can be represented by the equation: 6Li + N2 → 2Li3N [[2]]

Equation 3: Li + H2O → ?

The reaction between lithium (Li) and water (H2O) in the presence of air can be represented by the equation: 2Li + 2H2O → 2LiOH + H2 [[3]]

Equation 4: Li2O + CO2 → ?

The reaction between lithium oxide (Li2O) and carbon dioxide (CO2) in the presence of air can be represented by the equation: Li2O + CO2 → Li2CO3 [[4]]

Oxidation-Reduction Reactions:

1) The reaction between lithium (Li) and oxygen (O2) can be considered as an oxidation-reduction reaction. In this reaction, lithium is oxidized from 0 to +1 oxidation state, while oxygen is reduced from 0 to -2 oxidation state [[1]].

2) The reaction between lithium (Li) and nitrogen (N2) can also be considered as an oxidation-reduction reaction. In this reaction, lithium is oxidized from 0 to +1 oxidation state, while nitrogen is reduced from 0 to -3 oxidation state [[2]].

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