Question

Ребят помогите пожалуйста. Очень нужно. Заранее благодарна! :) 1. Напишите уравнения реакции сульфата меди с : олово,серебро,оксид железа(3),хлорид бария. 2. Помогите пожалуйста решить задачу. Дано вещество KAl(SO4)2 . Вычислите массовую долю калия и алюминия в данной соли

Answer 1

1.

CuSO4+Sn=SnSO4+Cu↓

 

CuSO4+Ag=

Реакция :НЕ  ИДЕТ ! Элемент стоит в электрохимическом ряду напряжений металлов правее меди.   CuSO4+BaCl2=CuCl+BaSO4↓   2. M(KAl(SO4)2) =262 г/моль   W(K)=39/262=15% W(Al)=27/262=10%  

Answer 2

I can help you with your questions.

1. The reaction equations of copper sulfate with tin, silver, iron (III) oxide, and barium chloride are as follows:

- Copper sulfate reacts with tin to produce copper and tin (II) sulfate:

CuSO₄ + Sn → Cu + SnSO₄

- Copper sulfate reacts with silver to produce copper and silver sulfate:

CuSO₄ + 2Ag → Cu + Ag₂SO₄

- Copper sulfate reacts with iron (III) oxide to produce copper (II) oxide and iron (III) sulfate:

3CuSO₄ + 2Fe₂O₃ → 3CuO + 2Fe₂(SO₄)₃

- Copper sulfate reacts with barium chloride to produce copper (II) chloride and barium sulfate:

CuSO₄ + BaCl₂ → CuCl₂ + BaSO₄

2. To calculate the mass fraction of potassium and aluminum in the salt KAl(SO₄)₂, we need to know the molar masses of the elements and the compound. The molar masses are:

- Potassium: 39.1 g/mol - Aluminum: 26.98 g/mol - Sulfur: 32.06 g/mol - Oxygen: 16 g/mol - KAl(SO₄)₂: 258.2 g/mol

The mass fraction of an element is the ratio of the mass of that element in one mole of the compound to the molar mass of the compound. Therefore, the mass fractions of potassium and aluminum are:

- Potassium: 39.1 / 258.2 = 0.1514 or 15.14% - Aluminum: 26.98 / 258.2 = 0.1045 or 10.45%

I hope this helps. If you have any other questions, please feel free to ask.