Question

Fe2O3+C= ?SnO2+C=?расставить коэффициенты,написать электронный баланс

Answer 1

+3 -2        0        0       +2 -2

Fe2O3 + 3C =  2Fe + 3CO

     3|C[0] -2e  = C [+2]  | восстановитель, окисление

     2|Fe[+3] +3e = Fe[0]  | окислитель, восстановление

 

+4 -2        0        0   +2 -2

SnO2 + 2C =   Sn+ 2CO

     2|C[0] -2e  = C [+2]  | восстановитель, окисление

     1|Sn[+4] +4e = Sn[0]  | окислитель, восстановление

Answer 2

2Fe2O3+3C=4Fe+3CO2

 

4I Fe(3+) +3e=Fe(0)окислитель востановление

3I C(0) -4e=C(4+) востановитель окисление

 

SnO2+C=Sn+CO2

 

1I Sn(+4) -4e=Sn(0)окислитель востановление

1I C(0) -4e=C(4+) востановитель окисление

Answer 3

Fe2O3 + C = ?

To balance the equation Fe2O3 + C = ?, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's start by balancing the oxygen atoms. There are three oxygen atoms on the left side (Fe2O3) and none on the right side. To balance the oxygen atoms, we need to add three CO (carbon monoxide) molecules on the right side.

Fe2O3 + C = 3CO

Next, let's balance the carbon atoms. There is one carbon atom on the left side (C) and three carbon atoms on the right side (3CO). To balance the carbon atoms, we need to add a coefficient of 3 in front of the carbon on the left side.

3Fe2O3 + C = 3CO

Finally, let's balance the iron atoms. There are six iron atoms on the left side (3Fe2O3) and none on the right side. To balance the iron atoms, we need to add a coefficient of 6 in front of Fe on the right side.

3Fe2O3 + C = 6Fe + 3CO

Therefore, the balanced equation is:

3Fe2O3 + C = 6Fe + 3CO.

SnO2 + C = ?

To balance the equation SnO2 + C = ?, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's start by balancing the oxygen atoms. There are two oxygen atoms on the left side (SnO2) and none on the right side. To balance the oxygen atoms, we need to add two CO (carbon monoxide) molecules on the right side.

SnO2 + C = 2CO

Next, let's balance the carbon atoms. There is one carbon atom on the left side (C) and two carbon atoms on the right side (2CO). To balance the carbon atoms, we need to add a coefficient of 2 in front of the carbon on the left side.

SnO2 + 2C = 2CO

Finally, let's balance the tin atoms. There is one tin atom on the left side (SnO2) and none on the right side. To balance the tin atoms, we need to add a coefficient of 1 in front of Sn on the right side.

SnO2 + 2C = Sn + 2CO

Therefore, the balanced equation is:

SnO2 + 2C = Sn + 2CO.

Electron Balance

To write the electron balance for the given equations, we need to consider the oxidation states of the elements involved.

In the equation Fe2O3 + C = 6Fe + 3CO, the oxidation state of iron changes from +3 in Fe2O3 to 0 in Fe, while the oxidation state of carbon changes from 0 in C to +4 in CO. The total change in oxidation state is 3 electrons gained by iron and 4 electrons lost by carbon. Therefore, the electron balance for this equation is satisfied.

In the equation SnO2 + 2C = Sn + 2CO, the oxidation state of tin changes from +4 in SnO2 to 0 in Sn, while the oxidation state of carbon changes from 0 in C to +4 in CO. The total change in oxidation state is 4 electrons gained by tin and 4 electrons lost by carbon. Therefore, the electron balance for this equation is also satisfied.

Please note that the electron balance is based on the oxidation states of the elements and does not take into account the actual transfer of electrons during the reaction.