Question

Помогите,пожалуйста:)Напишите уравнения реакций,с помощью которых можно осуществить следующие превращения:1)CH3-CH2-CH2Br-->C3H6-->C3H6Br2-->C3H42)CH3-CH2-CH2Br-->C6H14

Answer 1

CH3-CH2-CH2Br+KOH(Спирт)=CH3-CH=CH2+KBr+H2O

CH3-CH=CH2+Br2=C3H6Br2

C3H6Br2+2KOH(спирт)=C3H4+2KBr+2H2O

2C3H7Br+2Na=C6H14+2NaBr

Answer 2

Conversion 1: CH3-CH2-CH2Br -> C3H6 -> C3H6Br2 -> C3H4

To achieve the desired transformations, we can use a series of reactions. Let's break it down step by step:

1. Conversion of CH3-CH2-CH2Br to C3H6: - The reaction involves the elimination of a bromine atom (Br) from CH3-CH2-CH2Br to form a double bond (C=C) in C3H6. - This reaction is known as a dehydrohalogenation reaction. - The specific reagent used for this reaction can vary, but commonly used reagents include strong bases like sodium ethoxide (NaOEt) or potassium tert-butoxide (KOtBu). - The reaction can be represented by the following equation: ``` CH3-CH2-CH2Br -> C3H6 + HBr ```

2. Conversion of C3H6 to C3H6Br2: - The reaction involves the addition of two bromine atoms (Br2) to the double bond (C=C) in C3H6 to form C3H6Br2. - This reaction is known as a halogenation reaction. - The reaction can be represented by the following equation: ``` C3H6 + Br2 -> C3H6Br2 ```

3. Conversion of C3H6Br2 to C3H4: - The reaction involves the elimination of two hydrogen atoms (H2) from C3H6Br2 to form a triple bond (C≡C) in C3H4. - This reaction is known as a dehalogenation reaction. - The specific reagent used for this reaction can vary, but commonly used reagents include zinc (Zn) and acetic acid (CH3COOH). - The reaction can be represented by the following equation: ``` C3H6Br2 + Zn -> C3H4 + ZnBr2 ```

Please note that the specific reaction conditions and reagents may vary depending on the desired reaction conditions and the specific reactants used. It is always important to consider the reaction conditions and consult reliable sources or experts for detailed information on specific reactions.

Conversion 2: CH3-CH2-CH2Br -> C6H14

To achieve the conversion of CH3-CH2-CH2Br to C6H14, we need to perform a reaction that increases the carbon chain length. One possible reaction is the Grignard reaction. Here's how it can be done:

1. Conversion of CH3-CH2-CH2Br to CH3-CH2-CH2-MgBr: - The reaction involves the reaction of CH3-CH2-CH2Br with magnesium (Mg) in the presence of an ether solvent (such as diethyl ether). - This reaction forms an organomagnesium compound known as a Grignard reagent. - The reaction can be represented by the following equation: ``` CH3-CH2-CH2Br + Mg -> CH3-CH2-CH2-MgBr ```

2. Conversion of CH3-CH2-CH2-MgBr to CH3-CH2-CH2-CH2-MgBr: - The reaction involves the reaction of CH3-CH2-CH2-MgBr with another molecule of CH3-CH2-CH2-Br. - This reaction extends the carbon chain length by one carbon atom. - The reaction can be represented by the following equation: ``` CH3-CH2-CH2-MgBr + CH3-CH2-CH2-Br -> CH3-CH2-CH2-CH2-MgBr ```

3. Conversion of CH3-CH2-CH2-CH2-MgBr to C6H14: - The reaction involves the reaction of CH3-CH2-CH2-CH2-MgBr with a suitable electrophile, such as water (H2O) or an acid. - This reaction replaces the magnesium atom with a hydrogen atom, resulting in the formation of the desired product, C6H14. - The reaction can be represented by the following equation: ``` CH3-CH2-CH2-CH2-MgBr + H2O -> C6H14 + MgBrOH ```

Again, it is important to note that the specific reaction conditions and reagents may vary depending on the desired reaction conditions and the specific reactants used. It is always recommended to consult reliable sources or experts for detailed information on specific reactions.