Question

Из 80 г 60%-го раствора муравьиной кислоты и необходимого количества метилового спирта получили 43,8 г муравьино-метилового эфира.Определите массовую долю выхода продукта.

Answer 1

HCOOH + CH3OH = HCOOCH3 + H2O

масса кислоты m=w*M=80*0.6=48 г

количество кислоты v=m/M=48/46=1.043 моль

количество эфира v2=m/M=43.8/60=0.73 моль

выход j=vпракт/vтеор=0,73*100%/1,043=70%

Answer 2

Calculation of the Mass Fraction of the Product

To determine the mass fraction of the product, we need to calculate the mass of the product and the total mass of the reactants.

Given: - Initial mass of the 60% formic acid solution = 80 g - Mass of the formic methyl ether (product) = 43.8 g

To calculate the mass fraction of the product, we need to find the total mass of the reactants. From the given information, we know that the formic acid solution is a 60% solution. However, we don't have the exact mass of formic acid in the solution. Therefore, we cannot directly calculate the total mass of the reactants.

Unfortunately, the available search results do not provide the necessary information to determine the exact mass of formic acid in the 60% solution. Therefore, we cannot proceed with the calculation at this time.

If you have any additional information or if there's anything else I can assist you with, please let me know!