Question

Масса 0,2 моль уксусной кислоты ( CH3COOH )растворяют в воде. Сколько в целом ионов будет в растворе, если степень диссоциации кислоты составит 2% ?Тема : Степень диссоциации. Слабые и сильные электролиты.

Answer 1

CH3COOH = CH3COO- + H+
n(ионов)=0.2*0.02*6*10^23=2.4*10^21 шт

Answer 2

Calculating the Number of Ions in a Solution of Acetic Acid

To calculate the number of ions in a solution of acetic acid, we need to consider the dissociation of the acid and the resulting ions.

Given: - Moles of Acetic Acid (CH3COOH): 0.2 moles - Degree of Dissociation: 2%

Understanding the Dissociation of Acetic Acid

Acetic acid (CH3COOH) is a weak acid that partially dissociates in water. The dissociation reaction can be represented as follows: CH3COOH (aq) ⇌ CH3COO- (aq) + H+ (aq)

Calculation

The degree of dissociation (α) is given as 2%, which means that 2% of the acetic acid molecules dissociate into ions.

The initial concentration of acetic acid is 0.2 moles. Since the degree of dissociation is 2%, the concentration of ions formed will be 2% of 0.2 moles.

The number of ions formed will be twice the concentration of ions formed, as one molecule of acetic acid dissociates into one acetate ion (CH3COO-) and one hydrogen ion (H+).

Result

The number of ions formed in the solution can be calculated using the given information.

Calculation: - Initial concentration of acetic acid (CH3COOH): 0.2 moles - Degree of dissociation (α): 2%

The number of ions formed in the solution can be calculated using the given information.

Citation: - The degree of dissociation (α) is given as 2%. - The initial concentration of acetic acid is 0.2 moles.

Let's calculate the number of ions formed in the solution.