Question

Железо здесь скольки валентное?K4[Fe(C2O4)3]

Answer 1

Определяется несложно-главное приручится:
K4[Fe(C2O4)3] убираем 4 плюсовых калия(4К(+))
[Fe(C2O4)3]⁻⁴ (C2O4) с.о=-2 Убираем 3 C2O4⁻² Суммарно -6
Fe²⁺
Двухвалентное

Answer 2

Valence of Iron in K4[Fe(C2O4)3]

The valence of iron in the compound K4[Fe(C2O4)3] can be determined by analyzing the oxidation state of iron and the overall charge of the compound.

The compound K4[Fe(C2O4)3] contains the complex ion [Fe(C2O4)3]^4-. The overall charge of the complex ion is 4- due to the presence of four potassium ions (K^+) with a charge of +1 each.

The oxalate ion (C2O4) has a charge of 2-.

To find the valence of iron, we can use the formula: \[ \text{Valence of Fe} = \frac{\text{Total charge of complex ion}}{\text{Number of Fe ions}} \]

Substituting the values: \[ \text{Valence of Fe} = \frac{-4}{1} = -4 \]

So, the valence of iron in K4[Fe(C2O4)3] is -4.

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