Question

из раствора массой 3 кг с массовой долей аммиачной селитры (удобрение) 20% при охлаждении выпало 100 г соли.Определите массовую долю соли в охлажденном растворе.

Answer 1

"амега"(она же массовая доля) = (3000*0,2 - 100)/(3000 - 100) = 0,1724*100% = 17,24%

Answer 2

Calculation of Mass Fraction of Salt in the Cooled Solution

To determine the mass fraction of salt in the cooled solution, we need to consider the initial mass of the solution and the mass of the salt that precipitated during cooling.

Given: - Initial mass of the solution = 3 kg - Mass fraction of ammonium nitrate fertilizer (NH4NO3) in the solution = 20% - Mass of salt precipitated during cooling = 100 g

To calculate the mass fraction of salt in the cooled solution, we can follow these steps:

1. Calculate the mass of ammonium nitrate fertilizer in the initial solution: - Mass of ammonium nitrate = Mass of solution * Mass fraction of ammonium nitrate - Mass of ammonium nitrate = 3 kg * 20% = 0.6 kg

2. Calculate the mass of water in the initial solution: - Mass of water = Mass of solution - Mass of ammonium nitrate - Mass of water = 3 kg - 0.6 kg = 2.4 kg

3. Calculate the mass fraction of salt in the cooled solution: - Mass fraction of salt = Mass of salt / (Mass of salt + Mass of water) - Mass fraction of salt = 100 g / (100 g + 2.4 kg) = 100 g / 2.5 kg = 0.04

Therefore, the mass fraction of salt in the cooled solution is 0.04 or 4%.

Please note that the calculation assumes that the mass of the solution remains constant during the cooling process and that there are no other components present in the solution that could affect the calculation.