Question

4. Расставьте коэффициенты, преобразовав схемы в уравнения реакций. Укажите тип каждой реакции. AgNO3 + Al → Ag + Al(NO3)3 Fe(NO3)3 →Fe2O3 + NO2 + O2 P + O2 →P2O3 CaCl2 + AgNO3 →CaNO3 + AgCl Mg + H2SO4 → MgSO4 + H2 KClO3 →KCl + KClO4 P4 + Cl2 → PCl5 K + H2O →KOH + H2 NaNO3 → NaNO2 + O2 Na2SO4 + BaCl2 →NaCl + BaSO4

Answer 1

Ответ:
3AgNO3 + Al → 3Ag + Al(NO3)3(замещения)
4Fe(NO3)3 →2Fe2O3 +12NO2 +3 O2(разложение)
4P +3 O2 →2P2O3(реакция присоединения)
CaCl2 + 2AgNO3 →Ca(NO3)2 + 2AgCl(реакция обмена)
Mg + H2SO4 → MgSO4 + H2(замещения)
4KClO3 = 3KClO4 + KCl(разложение)
2P +5 Cl2 → 2PCl5(это реакция присоединения)
2K + 2H2O →2KOH + H2(это реакция присоединения)
2NaNO3 → 2NaNO2 +O2(это реакция разложения)
Na2SO4 + BaCl2 →2NaCl + BaSO4(белый осадок и качественная реакция на соли бария)-Это  реакция обмена

Answer 2

Balancing Chemical Equations

To balance the given chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's go through each equation and balance them one by one.

1. AgNO3 + Al → Ag + Al(NO3)3

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides. Let's start with the aluminum (Al) atoms. There is one Al atom on the left side and one Al atom on the right side, so it is already balanced. Next, let's balance the silver (Ag) atoms. There is one Ag atom on the left side and one Ag atom on the right side, so it is also balanced. Finally, let's balance the nitrogen (N) and oxygen (O) atoms in the nitrate (NO3) ions. There are three NO3 ions on the left side, which contain a total of three N atoms and nine O atoms. To balance this, we need three Al(NO3)3 molecules on the right side, which will provide a total of three N atoms and nine O atoms. Therefore, the balanced equation is:

AgNO3 + Al → Ag + Al(NO3)3 [[1]]

Type of reaction: Single displacement reaction

2. Fe(NO3)3 → Fe2O3 + NO2 + O2

To balance this equation, let's start with the iron (Fe) atoms. There is one Fe atom on the left side and two Fe atoms on the right side, so we need to multiply Fe(NO3)3 by 2 to balance the Fe atoms. Next, let's balance the nitrogen (N) atoms. There are three N atoms on the left side and none on the right side, so we need to add three NO2 molecules on the right side to balance the N atoms. Finally, let's balance the oxygen (O) atoms. There nine O atoms on the left side (three from Fe(NO3)3 and six from NO3), and we can balance them by adding four O2 molecules on the right side. Therefore, the balanced equation is:

2 Fe(NO3)3 → Fe2O3 + 3 NO2 + 4 O2 [[2]]

Type of reaction: Decomposition reaction

3. P + O2 → P2O3

To balance this equation, let's start with the phosphorus (P) atoms. There is one P atom on the left side and two P atoms on the right side, so we need to multiply P by 2 to balance the P atoms. Next, let's balance the oxygen (O) atoms. There are two O atoms on the left side and three O atoms on the right side, so we need to multiply O2 by 1.5 to balance the O atoms. However, we cannot have fractional coefficients in a balanced equation, so we can multiply the entire equation by 2 to get whole number coefficients. Therefore, the balanced equation is:

4 P + 3 O2 → 2 P2O3 [[3]]

Type of reaction: Combination reaction

4. CaCl2 + AgNO3 → Ca(NO3)2 + AgCl

To balance this equation, let's start with the calcium (Ca) atoms. There is one Ca atom on the left side and one Ca atom on the right side, so it is already balanced. Next, let's balance the chlorine (Cl) atoms. There are two Cl atoms on the left side and one Cl atom on the right side, so we need to multiply AgCl by 2 to balance the Cl atoms. Finally, let's balance the nitrogen (N) and oxygen (O) atoms in the nitrate (NO3) ions. There are two NO3 ions on the left side, which contain a total of two N atoms and six O atoms. To balance this, we need two Ca(NO3)2 molecules on the right side, which will provide a total of two N atoms and six O atoms. Therefore, the balanced equation is:

CaCl2 + 2 AgNO3 → Ca(NO3)2 + 2 AgCl [[4]]

Type of reaction: Double displacement reaction

5. Mg + H2SO4 → MgSO4 + H2

To balance this equation, let's start with the magnesium (Mg) atoms. There is one Mg atom on the left side and one Mg atom on the right side, so it is already balanced. Next, let's balance the hydrogen (H) atoms. There are two H atoms on the left side and two H atoms on the right side, so it is also balanced. Finally, let's balance the sulfur (S) and oxygen (O) atoms in the sulfate (SO4) ion. There is one SO4 ion on the left side, which contains one S atom and four O atoms. To balance this, we need one MgSO4 molecule on the right side, which will provide one S atom and four O atoms. Therefore, the balanced equation is:

Mg + H2SO4 → MgSO4 + H2 [[5]]

Type of reaction: Single displacement reaction

6. KClO3 → KCl + KClO4

To balance this equation, let's start with the potassium (K) atoms. There is one K atom on the left side and two K atoms on the right side, so we need to multiply KCl by 2 to balance the K atoms. Next, let's balance the chlorine (Cl) atoms. There are three Cl atoms on the left side and one Cl atom on the right side, so we need to multiply KClO3 by 3 to balance the Cl atoms. Therefore, the balanced equation is:

2 KClO3 → 2 KCl + KClO4 [[6]]

Type of reaction: Decomposition reaction

7. P4 + Cl2 → PCl5

To balance this equation, let's start with the phosphorus (P) atoms. There are four P atoms on the left side and one P atom on the right side, so we need to multiply PCl5 by 4 to balance the P atoms. Next, let's balance the chlorine (Cl) atoms. There are two Cl atoms on the left side and five Cl atoms on the right side, so we need to multiply Cl2 by 5 to balance the Cl atoms. Therefore, the balanced equation is:

4 P4 + 5 Cl2 → 10 PCl5 [[7]]

Type of reaction: Combination reaction

8. K + H2O → KOH + H2

To balance this equation, let's start with the potassium (K) atoms. There is one K atom on the left side and one K atom on the right side, so it is already balanced. Next, let's balance the hydrogen (H) atoms. There are two H atoms on the left side and two H atoms on the right side, so it is also balanced. Finally, let's balance the oxygen (O) atoms. There is one O atom on the left side and one O atom on the right side, so it is already balanced. Therefore, the balanced equation is:

K + H2O → KOH + H2 [[8]]

Type of reaction: Single displacement reaction

9. NaNO3 → NaNO2 + O2

To balance this equation, let's start with the sodium (Na) atoms. There is one Na atom on the left side and one Na atom on the right side, so it is already balanced. Next, let's balance the nitrogen (N) atoms. There is one N atom on the left side and one N atom on the right side, so it is also balanced. Finally, let's balance the oxygen (O) atoms. There three O atoms on the left side and two O atoms on the right side, so we need to multiply NaNO2 by 1.5 to balance the O atoms. However, we cannot have fractional coefficients in a balanced equation, so we can multiply the entire equation by 2 to get whole number coefficients. Therefore, the balanced equation is:

2 NaNO3 → 2 NaNO2 + 3 O2 [[9]]

Type of reaction: Decomposition reaction

10. Na2SO4 + BaCl2 → 2 NaCl + BaSO4

To balance this equation, let's start with the sodium (Na) atoms. There are two Na atoms on the left side and two Na atoms on the right side, so it is already balanced. Next, let's balance the chlorine (Cl) atoms. There are two Cl atoms on the left side and two Cl atoms on the right side, so it is also balanced. Finally, let's balance the sulfur (S) and oxygen (O) atoms in the sulfate (SO4) ion. There is one SO4 ion on the left side, which contains one S atom and four O atoms. To balance this, we need one BaSO4 molecule on the right side, which will provide one S atom and four O atoms. Therefore, the balanced equation is:

Na2SO4 + BaCl2 → 2 NaCl + BaSO4 [[10]]

Type of reaction: Double displacement reaction

I hope this helps! Let me know if you have any further questions.