Question

Составить уравнения реакцииMnCl2+(NH4)2HPO4=(продукт 1й реакции)+KBrO3+HNO3=MnNH4PO4+CH3COOH=[Cd(NH3)4]Cl2+HCl=CrPO4+NaOH+H2O2=

Answer 1

1) MnCl2 + (NH4)2HPO4 = MnHPO4↓ + 2NH4Cl;

2) 6MnHPO4 + 5KBrO3 + 9H2O = 6HMnO4 + 6H3PO4 + 5KBr (баланс см. в комм-х);

3) MnNH4PO4 + CH3COOH =MnHPO4↓ + CH3COONH4;

4) [Cd(NH3)4]Cl2 + 4HCl = CdCl2 + 4NH4Cl;

5) 2CrPO4 + 10NaOH + 3H2O2 = 2Na2CrO4 + 2Na3PO4 + 8H2O.

Answer 2

Balancing the Equations:

Let's balance the given chemical equations one by one:

1. MnCl2 + (NH4)2HPO4 = (product of the first reaction)

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

MnCl2 + (NH4)2HPO4 = MnNH4PO4 + 2NH4Cl 2. KBrO3 + HNO3 = MnNH4PO4 + CH3COOH

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

2KBrO3 + 5HNO3 = 3Mn(NO3)2 + 2CH3COOH + 2H2O + 2KNO3 + Br2 3. [Cd(NH3)4]Cl2 + HCl = CrPO4 + NaOH + H2O2

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the balanced equation:

[Cd(NH3)4]Cl2 + 4HCl = CrPO4 + 4NH4Cl 4. CrPO4 + NaOH + H2O2 = (product of the fourth reaction)

Unfortunately, the snippet provided does not contain the balanced equation for the fourth reaction. However, I can provide you with the general steps to balance the equation:

1. Count the number of atoms of each element on both sides of the equation. 2. Start by balancing the elements that appear in only one compound on each side. 3. Balance the remaining elements by adjusting the coefficients of the compounds. 4. Check that the number of atoms of each element is the same on both sides of the equation.

I apologize for not being able to provide the balanced equation for the fourth reaction. If you have any other questions, feel free to ask!