Question

Расписать 1 уравнение на ионное????Все решено уже 4Mg + 5H2SO4 = 4MgSO4 + H2S + 4H2O H2SO4+BaCl2=BaSO4+2HCl Na2SO4+BaCl2=2NaCl+BaSO4 Na2CO3+BaCI2=2NaCI+BaCO3 (осадок) BaCO3 + H2SO4 → BaSO4 + CO2 + H2O

Answer 1

Na₂SO₄ + BaCl₂ = BaSO₄↓ + 2NaCl
2Na⁺ + SO₄²⁻ + Ba²⁺ + 2Cl⁻ = BaSO₄↓ + 2Na⁺ + 2Cl⁻
Ba²⁺ + SO₄²⁻ = BaSO₄↓

Answer 2

I can help you with chemistry questions. You asked me to write the first equation in ionic form. Here is the answer:

$$4\text{Mg} + 5\text{H}_2\text{SO}_4 = 4\text{MgSO}_4 + \text{H}_2\text{S} + 4\text{H}_2\text{O}$$

In ionic form, this equation can be written as:

$$4\text{Mg}^{2+} + 10\text{e}^- + 10\text{H}^+ + 5\text{SO}_4^{2-} = 4\text{Mg}^{2+} + 4\text{SO}_4^{2-} + \text{H}_2\text{S} + 4\text{H}_2\text{O}$$

To simplify, we can cancel out the common ions on both sides:

$$10\text{e}^- + 10\text{H}^+ + \text{SO}_4^{2-} = \text{H}_2\text{S} + 2\text{H}_2\text{O}$$

This is the net ionic equation for the reaction. I hope this helps.Ответь+подробно.+Расписать+1+уравнение+на+ионное????Все+решено+уже+4Mg+++5H2SO4+=+4MgSO4+++H2S+++4H2O+H2SO4+BaCl2=BaSO4+2HCl+Na2SO4+BaCl2=2NaCl+BaSO4+Na2CO3+BaCI2=2NaCI+BaCO3+(осадок)+BaCO3+++H2SO4+→+BaSO4+++CO2+++H2O