
Мына реакциялық теңдеуді аяқтап, теңестіру керек Cu(OH)2+H2SO4=


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Тип реакции: Двойная замена



Тип реакции: Двойная замена



Chemical Reaction of Cu(OH)2 and H2SO4
When copper(II) hydroxide (Cu(OH)2) reacts with sulfuric acid (H2SO4), a chemical reaction takes place. The reaction can be represented by the following equation:
Cu(OH)2 + H2SO4 → CuSO4 + 2H2O
This reaction results in the formation of copper(II) sulfate (CuSO4) and water (H2O) as products.
The balanced chemical equation shows that one molecule of copper(II) hydroxide reacts with one molecule of sulfuric acid to produce one molecule of copper(II) sulfate and two molecules of water.
This reaction is a classic example of an acid-base neutralization reaction, where an acid (sulfuric acid) reacts with a base (copper(II) hydroxide) to form a salt (copper(II) sulfate) and water.
The reaction can be further understood by considering the chemical properties of the substances involved and the principles of chemical bonding and reactivity.
In summary, the reaction of Cu(OH)2 and H2SO4 results in the formation of CuSO4 and water, following the principles of acid-base neutralization chemistry


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