Question

Сколько тепла следует сообщить 100г льда при температуре -10 градусов по С,чтобы превратить его в воду,имеющую температуру 75 градусов по С. Пользуясь уравнением Q=cm(T2-T1) не могу вспомнить что здесь "с"???

Answer 1

Удельная теплоемкость с    у льда 2100

Answer 2

Calculation of Heat Required to Convert Ice to Water

To calculate the amount of heat required to convert 100g of ice at -10°C to water at 75°C, we can use the equation Q = cm(T2 - T1), where Q is the heat energy, c is the specific heat capacity, m is the mass, T2 is the final temperature, and T1 is the initial temperature.

In this case, we need to find the specific heat capacity of ice. The specific heat capacity is the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius per unit mass.

Unfortunately, the specific heat capacity of ice is not provided in the search results. However, the specific heat capacity of ice is approximately 2.09 J/g°C

Using this value, we can proceed with the calculation:

Given: - Mass of ice (m) = 100g - Initial temperature (T1) = -10°C - Final temperature (T2) = 75°C - Specific heat capacity of ice (c) = 2.09 J/g°C

Calculation: Q = cm(T2 - T1)

Substituting the given values: Q = (2.09 J/g°C) * (100g) * (75°C - (-10°C))

Simplifying the equation: Q = (2.09 J/g°C) * (100g) * (85°C)

Calculating the result: Q = 17765 J

Therefore, 17765 Joules of heat should be supplied to convert 100g of ice at -10°C to water at 75°C.

Please note that the specific heat capacity of ice may vary slightly depending on the source, but the value provided here is a reasonable approximation.

I hope this helps! Let me know if you have any further questions.