Question

Расчитайте кол-во вещ-ва и массу оксида углерода (4),который образуется при взаимодействии 21.2г карбоната натрия с соляной кислотой.

Answer 1

Решение задачи находится на фото

Answer 2

Calculation of the Amount and Mass of Carbon Dioxide (CO2) Formed

To calculate the amount and mass of carbon dioxide (CO2) formed when 21.2 grams of sodium carbonate reacts with hydrochloric acid, we need to consider the balanced chemical equation for the reaction:

Na2CO3 + 2HCl -> 2NaCl + H2O + CO2

From the balanced equation, we can see that 1 mole of sodium carbonate (Na2CO3) reacts with 2 moles of hydrochloric acid (HCl) to produce 1 mole of carbon dioxide (CO2).

To calculate the amount of carbon dioxide formed, we need to convert the mass of sodium carbonate to moles using its molar mass. The molar mass of sodium carbonate (Na2CO3) is calculated as follows:

2(Na) + 1(C) + 3(O) = 2(22.99 g/mol) + 12.01 g/mol + 3(16.00 g/mol) = 105.99 g/mol

Now, we can calculate the number of moles of sodium carbonate:

moles of Na2CO3 = mass of Na2CO3 / molar mass of Na2CO3 moles of Na2CO3 = 21.2 g / 105.99 g/mol

To calculate the amount of carbon dioxide formed, we use the mole ratio from the balanced equation. Since the mole ratio of Na2CO3 to CO2 is 1:1, the number of moles of carbon dioxide formed is equal to the number of moles of sodium carbonate:

moles of CO2 = moles of Na2CO3

Finally, to calculate the mass of carbon dioxide formed, we multiply the number of moles of carbon dioxide by its molar mass:

mass of CO2 = moles of CO2 * molar mass of CO2

The molar mass of carbon dioxide (CO2) is calculated as follows:

1(C) + 2(O) = 12.01 g/mol + 2(16.00 g/mol) = 44.01 g/mol

Now, let's calculate the amount and mass of carbon dioxide formed:

moles of Na2CO3 = 21.2 g / 105.99 g/mol = 0.1997 mol (rounded to four decimal places) moles of CO2 = 0.1997 mol mass of CO2 = 0.1997 mol * 44.01 g/mol = 8.79 g (rounded to two decimal places)

Therefore, when 21.2 grams of sodium carbonate reacts with hydrochloric acid, approximately 0.1997 moles of carbon dioxide are formed, with a mass of approximately 8.79 grams.

Please note that the values provided are approximate due to rounding.

Answer:

The amount of carbon dioxide formed is approximately 0.1997 moles, and the mass of carbon dioxide formed is approximately 8.79 grams.