Question

Задача 2.1. Определите молярную массу газа, если его относительная плотность по воздуху равна 2,207.

Answer 1

Do - плотность по воздуху, 29 - относительная молекулярная масса воздуха

Есть формула: Do = Mr(газа)/29, нам известно, что Do = 2, подставим в формулу:

2 = х/29 - х - это молекулярная масса газа

х = 29*2=58

Мы знаем, что относительная моекулярная масса численно равна молярной массе этого соединения, вывод M = 29 г/моль

Answer 2

Task 2.1: Determining the molar mass of a gas with a relative density of 2.207

To determine the molar mass of a gas, we can use the concept of relative density. Relative density is the ratio of the density of a substance to the density of a reference substance, which is often air for gases. In this case, the relative density of the gas is given as 2.207 with respect to air.

To calculate the molar mass of the gas, we can use the following formula:

Molar mass = (Relative density) x (Molar mass of air)

The molar mass of air is approximately 28.97 g/mol.

Using the given relative density of 2.207, we can calculate the molar mass of the gas as follows:

Molar mass = 2.207 x 28.97 g/mol

Calculating the result:

Molar mass ≈ 63.89 g/mol

Therefore, the molar mass of the gas is approximately 63.89 g/mol.

Please note that the molar mass calculated here is an approximation based on the given relative density and the molar mass of air. The actual molar mass of the gas may vary depending on its composition.

I hope this helps! Let me know if you have any further questions.