Question

При взаимодействии 20г едкого натра с углекислым газом образуется соль.Рассчитайте,сколько граммов хлорида натрия образуется и какой объем оксида углерода(4) выделится при взаимодействии данной соли с соляной кислотой

Answer 1

2 * 40г/моль         106 г/моль

   2NaOH + CO2 = Na2CO3 + H2O    х= 106 г/моль *  20г /  2 * 40г/моль= 26,5г 

       20г                          хг

 106 г/моль                                  44 г/моль 

 Na2CO3 + HCl = NaCl + H2O + CO2             х= 44 г/моль *  26,5г /  2 * 106г/моль= 11г 

    26,5г                                                хг 

 

V(CO2) = Vm * m / M= 22,4 дм.куб.\моль * 11г \ 44г\моль=5,6  дм.куб.

 

 

 

Answer 2

Calculation of Sodium Chloride Formation

To calculate the amount of sodium chloride formed when 20 grams of hydrochloric acid reacts with carbon dioxide, we need to determine the balanced chemical equation for the reaction. The balanced equation is as follows:

HCl + CO2 → NaCl + H2O

From the equation, we can see that 1 mole of hydrochloric acid (HCl) reacts with 1 mole of carbon dioxide (CO2) to produce 1 mole of sodium chloride (NaCl) and 1 mole of water (H2O).

To calculate the amount of sodium chloride formed, we need to convert the given mass of hydrochloric acid to moles using its molar mass. The molar mass of hydrochloric acid (HCl) is approximately 36.46 g/mol.

Number of moles of HCl = Mass of HCl / Molar mass of HCl

Number of moles of HCl = 20 g / 36.46 g/mol ≈ 0.548 mol

Since the balanced equation shows a 1:1 ratio between hydrochloric acid and sodium chloride, the number of moles of sodium chloride formed will also be 0.548 mol.

To convert the number of moles of sodium chloride to grams, we can use its molar mass. The molar mass of sodium chloride (NaCl) is approximately 58.44 g/mol.

Mass of NaCl = Number of moles of NaCl × Molar mass of NaCl

Mass of NaCl = 0.548 mol × 58.44 g/mol ≈ 32.02 g

Therefore, approximately 32.02 grams of sodium chloride will be formed when 20 grams of hydrochloric acid reacts with carbon dioxide.

Volume of Carbon Dioxide Produced

To calculate the volume of carbon dioxide (CO2) produced when the sodium chloride reacts with hydrochloric acid, we need to determine the balanced chemical equation for the reaction. The balanced equation is as follows:

NaCl + HCl → CO2 + H2O

From the equation, we can see that 1 mole of sodium chloride (NaCl) reacts with 1 mole of hydrochloric acid (HCl) to produce 1 mole of carbon dioxide (CO2) and 1 mole of water (H2O).

To calculate the volume of carbon dioxide produced, we need to convert the number of moles of sodium chloride to moles of carbon dioxide using the balanced equation.

Since we know that 0.548 moles of sodium chloride is formed, we can conclude that 0.548 moles of carbon dioxide will be produced.

The volume of a gas can be calculated using the ideal gas law, which states that:

Volume (V) = Number of moles (n) × Molar volume (V_m)

The molar volume of a gas at standard temperature and pressure (STP) is approximately 22.4 liters/mol.

Volume of CO2 = Number of moles of CO2 × Molar volume of CO2 at STP

Volume of CO2 = 0.548 mol × 22.4 L/mol ≈ 12.27 L

Therefore, approximately 12.27 liters of carbon dioxide will be produced when the sodium chloride reacts with hydrochloric acid.

Please note that the above calculations are based on the given information and assumptions about the reaction conditions.