Question

Задача - какой обьем углекислого газа обработается при горении 48гр углерода если выход составил 90%

Answer 1

Дано:
m(C) = 48 r
η(CO2) = 90% или 0,9
Найти:
Vпр.(СО2)-?

М(С) = 12 г/моль
n(C) = m/M = 48г/12 г/моль = 4 моль
С+О2 = СО2
Из УХР следует, что n(CO2)=n(C) = 4 моль
n(пр. СО2) = 4 моль*0,9 = 3,6 моль
Vпр(СО2) = n(прСО2)*Vm = 3,6 моль*22,4 л/моль = 80,64 л
Ответ: 80,64 л

Answer 2

Calculating the Volume of Carbon Dioxide Produced

To calculate the volume of carbon dioxide produced when 48g of carbon burns with a 90% yield, we can use the following steps:

1. Determine the Chemical Equation for the Combustion of Carbon: The balanced chemical equation for the combustion of carbon can be represented as: ``` C + O2 -> CO2 ```

2. Calculate the Moles of Carbon: We first need to convert the mass of carbon to moles. The molar mass of carbon is approximately 12 g/mol. Therefore, the number of moles of carbon can be calculated as: ``` moles = mass / molar mass moles = 48g / 12 g/mol moles = 4 moles ```

3. Determine the Stoichiometry of the Reaction: From the balanced chemical equation, we can see that 1 mole of carbon produces 1 mole of carbon dioxide.

4. Calculate the Moles of Carbon Dioxide Produced: Since the stoichiometry of the reaction is 1:1, the moles of carbon dioxide produced will be the same as the moles of carbon burned, which is 4 moles.

5. Apply the Ideal Gas Law to Calculate Volume: The ideal gas law states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. Assuming standard temperature and pressure (STP), where T = 273 K and P = 1 atm, we can calculate the volume using the equation: ``` V = nRT/P V = (4 moles)(0.0821 L.atm/mol.K)(273 K)/(1 atm) V ≈ 8.49 L ```

Conclusion

When 48g of carbon burns with a 90% yield, the volume of carbon dioxide produced is approximately 8.49 liters at standard temperature and pressure (STP).