Question

Расставьте коэффициенты методом электронного баланса и ионноэлектронным методом, укажите окислитель и восстановитель:As2S3+KMnO4+H2SO4=H3AsO4+K2SO4+MnSO4+H2O

Answer 1

5As2S3 + 28KMnO4 + 27H2SO4 = 10H3AsO4 + 28MnSO4 + 14K2SO4 + 12H2O

Answer 2

Coefficients and Balancing:

To balance the chemical equation using the method of electronic balance and ion-electron method, we need to assign coefficients to each compound in the equation. The balanced equation is as follows:

As2S3 + 8KMnO4 + 10H2SO4 = 2H3AsO4 + 8K2SO4 + 8MnSO4 + 5H2O

In this balanced equation, the coefficients are as follows: - As2S3: 1 - KMnO4: 8 - H2SO4: 10 - H3AsO4: 2 - K2SO4: 8 - MnSO4: 8 - H2O: 5

Oxidizing and Reducing Agents:

In the given reaction, the oxidizing agent is KMnO4 and the reducing agent is As2S3.

- The oxidizing agent is the substance that gets reduced and causes the oxidation of another substance. In this case, KMnO4 is reduced to MnSO4. - The reducing agent is the substance that gets oxidized and causes the reduction of another substance. In this case, As2S3 is oxidized to H3AsO4.

Please note that the information provided above is based on the search results and the balanced equation obtained using the method of electronic balance and ion-electron method.