Question

H2moo4+na2so3 = mo3o8 + na2so4 + h2o метод полуреакций

Answer 1

3H2MoO4 +2e- = Mo3O8 + 2H2O + 2OH-    | 2 | 2 | 1 |

(SO3)2- -2e- + 2OH- = (SO4)2- + H2O         | 2 |    | 1 |;

3H2MoO4 + (SO3)2- = Mo3O8 + (SO4)2- + 3H2O;

3H2MoO4 + Na2SO3 = Mo3O8 + Na2SO4 + 3H2O.

Answer 2

Balancing the Chemical Equation Using the Half-Reaction Method

To balance the chemical equation H2MoO4 + Na2SO3 = Mo3O8 + Na2SO4 + H2O using the half-reaction method, we need to follow these steps:

1. Identify the Half-Reactions: - The first step is to separate the equation into two half-reactions: oxidation and reduction.

- The oxidation half-reaction involves the loss of electrons, while the reduction half-reaction involves the gain of electrons.

2. Balance the Atoms: - After identifying the half-reactions, balance the atoms in each half-reaction except for O and H.

3. Balance Oxygen Atoms: - Add H2O to balance the oxygen atoms.

4. Balance Hydrogen Atoms: - Add H+ to balance the hydrogen atoms.

5. Balance Charge: - Add electrons to one side of each half-reaction to balance the charges.

6. Equalize the Electrons: - Multiply each half-reaction by an integer to equalize the number of electrons in both half-reactions.

7. Combine the Half-Reactions: - Add the half-reactions together and simplify if necessary.

Let's proceed with balancing the given chemical equation using the half-reaction method.

Balancing the Half-Reactions

The given unbalanced chemical equation is: H2MoO4 + Na2SO3 = Mo3O8 + Na2SO4 + H2O

The balanced half-reactions for this equation are as follows:

Oxidation Half-Reaction: H2MoO4 → Mo3O8 Reduction Half-Reaction: Na2SO3 → Na2SO4

Balancing the Half-Reactions Step by Step

1. Balance the Atoms: - The atoms are already balanced in both half-reactions.

2. Balance Oxygen Atoms: - In the oxidation half-reaction, we need to balance the oxygen atoms by adding water (H2O).

Oxidation Half-Reaction: H2MoO4 → Mo3O8 + 4H2O

3. Balance Hydrogen Atoms: - In the oxidation half-reaction, we need to balance the hydrogen atoms by adding H+.

Oxidation Half-Reaction: H2MoO4 + 8H+ → Mo3O8 + 4H2O

4. Balance Charge: - The charges are not balanced in the oxidation half-reaction. We need to add electrons (e-) to balance the charges.

Oxidation Half-Reaction: H2MoO4 + 8H+ + 6e- → Mo3O8 + 4H2O

5. Equalize the Electrons: - Multiply the reduction half-reaction by 6 to equalize the number of electrons in both half-reactions.

Reduction Half-Reaction: 6Na2SO3 → 6Na2SO4

6. Combine the Half-Reactions: - Add the half-reactions together and simplify if necessary.

Overall Balanced Equation: H2MoO4 + 6Na2SO3 + 8H+ → Mo3O8 + 6Na2SO4 + 4H2O

This is the balanced chemical equation using the half-reaction method for the given reaction H2MoO4 + Na2SO3 = Mo3O8 + Na2SO4 + H2O.