Question

Вычисли, какая масса сульфида натрия образуется, если с серой прореагируют 0,92 г натрия.

Answer 1

2Na+S=Na2S

1)n(Na)=m/M=0,92/23=0,04

2)n(Na2S)=n/2(Na)=0,02

3) m(Na2S)=n*M=0,02*78=1,56 г

Answer 2

Calculation of the Mass of Sodium Sulfide Formed

To calculate the mass of sodium sulfide formed when reacting sulfur with 0.92 g of sodium, we need to determine the balanced chemical equation for the reaction between sodium and sulfur.

The balanced chemical equation for the reaction between sodium and sulfur is:

2 Na + S → Na2S

According to the balanced equation, 2 moles of sodium react with 1 mole of sulfur to produce 1 mole of sodium sulfide.

To calculate the mass of sodium sulfide formed, we need to convert the mass of sodium (0.92 g) to moles using the molar mass of sodium and then use the mole ratio from the balanced equation to determine the moles of sodium sulfide formed. Finally, we can convert the moles of sodium sulfide to grams using the molar mass of sodium sulfide.

Here are the steps to calculate the mass of sodium sulfide formed:

1. Calculate the moles of sodium: - Molar mass of sodium (Na) = 22.99 g/mol - Moles of sodium = mass of sodium / molar mass of sodium - Moles of sodium = 0.92 g / 22.99 g/mol

2. Use the mole ratio from the balanced equation to determine the moles of sodium sulfide formed: - According to the balanced equation, 2 moles of sodium react to form 1 mole of sodium sulfide. - Moles of sodium sulfide = (moles of sodium) / 2

3. Calculate the mass of sodium sulfide formed: - Molar mass of sodium sulfide (Na2S) = 78.04 g/mol - Mass of sodium sulfide = (moles of sodium sulfide) * (molar mass of sodium sulfide)

Let's calculate the mass of sodium sulfide formed using the given information:

1. Moles of sodium: - Molar mass of sodium (Na) = 22.99 g/mol - Moles of sodium = 0.92 g / 22.99 g/mol = 0.04 mol

2. Moles of sodium sulfide: - Moles of sodium sulfide = (moles of sodium) / 2 = 0.04 mol / 2 = 0.02 mol

3. Mass of sodium sulfide: - Molar mass of sodium sulfide (Na2S) = 78.04 g/mol - Mass of sodium sulfide = (moles of sodium sulfide) * (molar mass of sodium sulfide) = 0.02 mol * 78.04 g/mol = 1.56 g

Therefore, the mass of sodium sulfide formed when reacting 0.92 g of sodium with sulfur is approximately 1.56 grams.

Please note that the calculated mass is an approximation and may vary depending on the accuracy of the molar masses used.