Question

Вычислите процентное содержание элементов в фосфорной кислоте​

Answer 1

Ответ:

98 г.

Объяснение:

Масса раствора кислоты равна 600*1,7 = 1020г.

С содержанием кислоты 1020*85/100 =867г.

m=867 г

Находим добавленную массу P2O5+3H20 — 2H3PO4

v(P2O5)= 71г/142г/моль=0,5 моль

0,5 * 2 = 1 моль

m(. H3PO4)= 98 г/моль*1моль=98г

m = 98 г.

Answer 2

Calculation of the Percentage Composition of Phosphoric Acid

To calculate the percentage composition of phosphoric acid (H3PO4), we need to determine the percentage of each element present in the compound.

Phosphoric acid (H3PO4) consists of hydrogen (H), phosphorus (P), and oxygen (O). We can calculate the percentage composition of each element by dividing the molar mass of the element by the molar mass of the compound and multiplying by 100.

The molar mass of phosphoric acid (H3PO4) can be calculated as follows: - Molar mass of hydrogen (H) = 1 g/mol - Molar mass of phosphorus (P) = 31 g/mol - Molar mass of oxygen (O) = 16 g/mol

Therefore, the molar mass of phosphoric acid (H3PO4) is: (3 * 1 g/mol) + (1 * 31 g/mol) + (4 * 16 g/mol) = 98 g/mol

Now, let's calculate the percentage composition of each element in phosphoric acid:

1. Hydrogen (H): - Number of moles of hydrogen (H) = 3 - Molar mass of hydrogen (H) = 1 g/mol - Percentage of hydrogen (H) = (3 * 1 g/mol) / 98 g/mol * 100 = 3.06%

2. Phosphorus (P): - Number of moles of phosphorus (P) = 1 - Molar mass of phosphorus (P) = 31 g/mol - Percentage of phosphorus (P) = (1 * 31 g/mol) / 98 g/mol * 100 = 31.63%

3. Oxygen (O): - Number of moles of oxygen (O) = 4 - Molar mass of oxygen (O) = 16 g/mol - Percentage of oxygen (O) = (4 * 16 g/mol) / 98 g/mol * 100 = 65.31%

Therefore, the percentage composition of elements in phosphoric acid (H3PO4) is approximately: - Hydrogen (H): 3.06% - Phosphorus (P): 31.63% - Oxygen (O): 65.31%

Please note that the percentages are approximate and rounded to two decimal places.