Question

при взаимодействии 10 грамм оксида магния с серной кислотой получен сульфат магния массой 6,4 г Рассчитайте массовую долю выхода продукта реакции​

Answer 1

Ответ:

W=mв-ва/mр-ра*100=26,4/10*100=2,64%.

Answer 2

Calculating the Mass Fraction of the Reaction Product

When 10 grams of magnesium oxide reacts with sulfuric acid to produce magnesium sulfate with a mass of 6.4 grams, we can calculate the mass fraction of the reaction product using the following steps:

1. Determine the Molar Mass of Magnesium Sulfate (MgSO4) - The molar mass of magnesium sulfate (MgSO4) is 24.305 + 32.065 + (4 * 15.999) = 120.366 g/mol.

2. Calculate the Number of Moles of Magnesium Sulfate Produced - The number of moles of magnesium sulfate produced can be calculated using the formula: \[ \text{moles} = \frac{\text{mass}}{\text{molar mass}} \] - Substituting the given mass of magnesium sulfate (6.4 grams) and its molar mass, we get: \[ \text{moles} = \frac{6.4}{120.366} = 0.0532 \, \text{moles} \]

3. Calculate the Mass Fraction of Magnesium Sulfate - The mass fraction of magnesium sulfate can be calculated using the formula: \[ \text{mass fraction} = \frac{\text{mass of magnesium sulfate produced}}{\text{total mass of products}} \times 100\% \] - Substituting the given mass of magnesium sulfate (6.4 grams) and the total mass of the products, we get: \[ \text{mass fraction} = \frac{6.4}{10} \times 100\% = 64\% \]

Conclusion

The mass fraction of the magnesium sulfate produced in the reaction is 64%.