Question

Ba(OH)2-BaO-BaCl2-BaCO3-CO2 K2CO3-CO2-H2CO3-Na2CO3-BaCO3 Al(OH)3-Al2O3-Al2(SO4)3-Al(OH)3-AlCl3

Answer 1

Ответ:

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Answer 2

The given sequence of chemical reactions involves the compounds Ba(OH)2, BaO, BaCl2, BaCO3, CO2, K2CO3, H2CO3, Na2CO3, Al(OH)3, Al2O3, and Al2(SO4)3. Let's break down the reactions step by step:

1. Ba(OH)2 → BaO + H2O: - Ba(OH)2 decomposes into BaO (barium oxide) and H2O (water) [[1]].

2. BaO + HCl → BaCl2: - BaO reacts with HCl (hydrochloric acid) to form BaCl2 (barium chloride) [[2]].

3. BaCl2 + Na2CO3 → BaCO3 + 2NaCl: - BaCl2 reacts with Na2CO3 (sodium carbonate) to produce BaCO3 (barium carbonate) and 2NaCl (sodium chloride) [[3]].

4. BaCO3 → BaO + CO2: - BaCO3 decomposes into BaO and CO2 (carbon dioxide) [[4]].

5. K2CO3 + CO2 + H2O → 2KHCO3: - K2CO3 (potassium carbonate) reacts with CO2 and H2O to form 2KHCO3 (potassium bicarbonate) [[5]].

6. H2CO3 → CO2 + H2O: - H2CO3 (carbonic acid) decomposes into CO2 and H2O [[6]].

7. Na2CO3 + H2O + CO2 → 2NaHCO3: - Na2CO3 reacts with H2O and CO2 to produce 2NaHCO3 (sodium bicarbonate) [[7]].

8. BaCO3 + Al(OH)3 → Al2(CO3)3 + Ba(OH)2: - BaCO3 reacts with Al(OH)3 (aluminum hydroxide) to form Al2(CO3)3 (aluminum carbonate) and Ba(OH)2 [[8]].

9. Al(OH)3 → Al2O3 + 3H2O: - Al(OH)3 decomposes into Al2O3 (aluminum oxide) and 3H2O [[9]].

10. Al2(SO4)3 + 6H2O → 2Al(OH)3 + 3H2SO4: - Al2(SO4)3 (aluminum sulfate) reacts with 6H2O to produce 2Al(OH)3 and 3H2SO4 (sulfuric acid) [[10]].

11. Al(OH)3 + 3HCl → AlCl3 + 3H2O: - Al(OH)3 reacts with 3HCl to form AlCl3 (aluminum chloride) and 3H2O [[11]].

Please note that the given reactions are simplified representations and may not account for all possible side reactions or conditions.