Question

Расставьте коэффициенты в приведенных ниже схемах химических реакций, определите тип реакции. 1. C+CO2→CO 2. Na+H2O→NaOH+H2 3. BaO+H2O→Ba(OH)2 4. Si+O2→SiO2 5. NO2+Mg→MgO+N2

Answer 1

Ответ:

Объяснение:

C + CO2 = 2CO (соединение)

2Na + 2H2O = 2NaOH + H2 (замещение)

BaO + H2O = Ba(OH)2 (соединение)

Si + O2 = SiO2 (соединение)

2NO2 + 4Mg = 4MgO + N2 (замещение)

Answer 2

Chemical Reactions and Coefficients

Here are the balanced chemical equations with coefficients for the given reactions:

1. C + CO2 → 2CO - Type of reaction: Reduction-Oxidation (Redox) reaction. This reaction involves the transfer of electrons between the reactants.

2. 2Na + 2H2O → 2NaOH + H2 - Type of reaction: Single displacement (or replacement) reaction. In this reaction, sodium (Na) displaces hydrogen (H) from water (H2O) to form sodium hydroxide (NaOH) and hydrogen gas (H2).

3. BaO + H2O → Ba(OH)2 - Type of reaction: Double displacement (or metathesis) reaction. In this reaction, barium oxide (BaO) reacts with water (H2O) to form barium hydroxide (Ba(OH)2).

4. Si + O2 → SiO2 - Type of reaction: Combination (or synthesis) reaction. This reaction involves the combination of silicon (Si) and oxygen (O2) to form silicon dioxide (SiO2).

5. 2NO2 + 4Mg → 2MgO + N2 - Type of reaction: Combustion reaction. In this reaction, nitrogen dioxide (NO2) reacts with magnesium (Mg) to form magnesium oxide (MgO) and nitrogen gas (N2).

Please note that the coefficients in the balanced equations represent the relative amounts of each substance involved in the reaction.