Question

для получения хлорида водорода в химической лаборатории израсходовано 4,44 г поваренной соли. Какой объем HCL можно получить в данном процессе, принимая выход продукта равным 100%?​

Answer 1

Відповідь:

1,7 л

Пояснення:

n(NaCl) = m(NaCl) / Mr(NaCl) = 4,44 г / 58,5г/моль = 0,0758 моль

2NaCl + H2SO4 = 2HCl + Na2SO4

мольное соотношение за реакцией равно 2   2

                                         за задачей      0,0758     0,0758

V(HCl) = n (HCl) * Vm = 0,0758 моль * 22,4 л/моль = 1,7 л

Answer 2

Calculating the Volume of HCl Produced from 4.44g of Table Salt

To calculate the volume of hydrogen chloride (HCl) produced from 4.44g of table salt (sodium chloride, NaCl), we can use the stoichiometry of the reaction between table salt and an acid, such as hydrochloric acid (HCl).

The balanced chemical equation for the reaction between table salt and hydrochloric acid is:

NaCl + HCl → NaCl + H2

From the balanced equation, we can see that 1 mole of NaCl reacts with 1 mole of HCl to produce 1 mole of H2. We can use this information to calculate the volume of HCl produced.

Calculation Steps

1. Calculate the moles of NaCl: - The molar mass of NaCl is approximately 58.44 g/mol. - Therefore, the moles of NaCl can be calculated as: ``` Moles of NaCl = Mass of NaCl / Molar mass of NaCl = 4.44g / 58.44 g/mol ≈ 0.076 moles ```

2. Calculate the moles of HCl: - Since the reaction is 1:1, the moles of HCl produced will be the same as the moles of NaCl: ``` Moles of HCl = 0.076 moles ```

3. Convert moles to volume: - The volume of a gas at standard temperature and pressure (STP) can be calculated using the ideal gas law, where 1 mole of any gas occupies 22.4 liters at STP. - Therefore, the volume of HCl produced can be calculated as: ``` Volume of HCl = Moles of HCl * 22.4 L/mol = 0.076 moles * 22.4 L/mol ≈ 1.70 liters ```

Conclusion

From 4.44g of table salt, approximately 1.70 liters of hydrogen chloride (HCl) can be produced in this process, assuming a 100% yield of the product.