8.Укажіть масову частку Оксигену в речовині,формула якої CaCO3. 16 32 48 52
Ответы на вопрос
Ответ: 48
Дано:
СаСО3
Знайти:
ω(О)-?
Объяснение:
Mr(CaCO3) = 40+12+16*3 = 100
ω(O) = 48/100 = 0,48 або 48%
Відповідь: 48
Mass Fraction of Oxygen in CaCO3
The mass fraction of oxygen in the substance with the formula CaCO3 can be calculated by considering the molar mass of each element in the compound.
The molar mass of CaCO3 can be calculated as follows: - Calcium (Ca) has a molar mass of approximately 40.08 g/mol. - Carbon (C) has a molar mass of approximately 12.01 g/mol. - Oxygen (O) has a molar mass of approximately 16.00 g/mol.
Using these molar masses, we can calculate the mass fraction of oxygen in CaCO3.
The formula for calcium carbonate (CaCO3) consists of one calcium atom (Ca), one carbon atom (C), and three oxygen atoms (O).
To calculate the mass fraction of oxygen in CaCO3, we can use the following steps:
1. Calculate the molar mass of CaCO3: - Molar mass of CaCO3 = (1 * molar mass of Ca) + (1 * molar mass of C) + (3 * molar mass of O)
2. Calculate the mass of oxygen in CaCO3: - Mass of oxygen = (3 * molar mass of O)
3. Calculate the mass fraction of oxygen: - Mass fraction of oxygen = (Mass of oxygen / Molar mass of CaCO3) * 100%
Let's perform the calculations:
- Molar mass of CaCO3 = (1 * 40.08 g/mol) + (1 * 12.01 g/mol) + (3 * 16.00 g/mol) = 100.09 g/mol - Mass of oxygen = (3 * 16.00 g/mol) = 48.00 g - Mass fraction of oxygen = (48.00 g / 100.09 g) * 100% ≈ 47.97%
Therefore, the mass fraction of oxygen in the substance with the formula CaCO3 is approximately 47.97%.
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