Question

У якому об'ємі води потрібно розчинити глюкозу кількістю речовини 1,5 моль щоб приготувати розчин з масовою часткою вуглеводу 20%?

Answer 1

Ответ:

Объяснение:

М(С6Н12О6) = 180 г/моль

m(C6H12O6) = n*M = 1,5 моль*180 г/моль = 270 г

Визначаємо масу розчину глюкози:

m(р-ну) = m(C6H12O6)/ω = 270 г/0,2 = 1350 г

Визначаємо масу води:

m(H2O) = m(р-ну)-m(С6Н12О6) = 1350 г - 270 г = 1080 г

ρ(Н2О) = 1 г/мл

Визначаємо об'єм води:

V(H2O) = m(H2O)/ρ(Н2О) = 1080 г/1 г/мл = 1080 мл

Відповідь: 1080 мл

Answer 2

Calculating the Volume of Water Needed to Dissolve Glucose

To calculate the volume of water needed to dissolve a certain amount of glucose to prepare a solution with a specific mass fraction of the carbohydrate, we can use the formula:

Mass fraction = (mass of solute / total mass of solution) * 100%

Given: - Amount of substance (glucose) = 1.5 moles - Mass fraction of carbohydrate = 20%

We can use the molar mass of glucose to calculate the mass of glucose needed and then use it to find the volume of water required.

First, let's calculate the mass of glucose needed.

The molar mass of glucose (C6H12O6) can be calculated as follows: - Carbon (C) molar mass = 12.01 g/mol - Hydrogen (H) molar mass = 1.008 g/mol - Oxygen (O) molar mass = 16.00 g/mol

Molar mass of glucose = (6 * 12.01) + (12 * 1.008) + (6 * 16.00) = 180.16 g/mol

Now, we can calculate the mass of glucose needed: Mass of glucose = moles of glucose * molar mass of glucose Mass of glucose = 1.5 moles * 180.16 g/mol

Let's calculate the mass of glucose and then proceed to find the volume of water required.