Question

На нейтралізацію 380 г 9%-го розчину гідроксиду металу А витратили 0,2 моль сульфатної кислоти. Обчисліть молярну масу металу А.

Answer 1

Объяснение:

А(ОН)2 + H2SO4 = ASO4 + 2H2O

m(AOH)= m(розч.)×w(AOH)= 380×0.09= 34,2

M(AOH)= x+(16+1)•2= x+17 г/моль

n(АОН)= n(H2SO4)

m/M (AOH) = n(H2SO4)

34.2/(x+34) = 0.2

0.2x+6.8=34.2

x= 137 (Ba) барій

Ва(ОН)2 + H2SO4 = ВаSO4↓ + 2H2O

Answer 2

To calculate the molar mass of metal A, we need to use the information given about the neutralization reaction between a 380 g 9% solution of metal hydroxide A and 0.2 moles of sulfuric acid.

Given information:

- Mass of metal hydroxide A solution: 380 g - Concentration of the metal hydroxide A solution: 9% - Moles of sulfuric acid used: 0.2 mol

Steps to calculate the molar mass of metal A:

1. Calculate the mass of metal hydroxide A in the solution: - Mass of metal hydroxide A = 380 g * 0.09 = 34.2 g

2. Calculate the moles of metal hydroxide A: - Moles of metal hydroxide A = Mass of metal hydroxide A / Molar mass of metal hydroxide A

3. Use the balanced chemical equation for the neutralization reaction to determine the stoichiometric ratio between metal hydroxide A and sulfuric acid.

4. Since 0.2 moles of sulfuric acid were used, we can determine the moles of metal hydroxide A: - Moles of metal hydroxide A = 0.2 mol * (moles of metal hydroxide A / moles of sulfuric acid)

5. Substitute the calculated moles of metal hydroxide A into the equation from step 2 and solve for the molar mass of metal A: - Molar mass of metal A = Mass of metal hydroxide A / Moles of metal hydroxide A

Please note that without the specific chemical formula for metal hydroxide A, we cannot provide an exact value for the molar mass of metal A.