Question

Напишіть рівняння реакції кисню з: а) амоніаком NH3, якщо в утвореному оксиді валентність Нітрогену дорівнює 2;б) розрахуйте масову частку Оксигену в цьому оксиді. ​

Answer 1

a) 4NH3 + 5O2 == 4NO + 6H2O

) W(O) = 16 / 30 * 100% = 53,33 %

Answer 2

Equation of the reaction of oxygen with ammonia (NH3) when the nitrogen in the resulting oxide has a valence of 2:

The equation for the reaction of oxygen with ammonia (NH3) can be represented as follows:

4 NH3 + 5 O2 → 4 NO2 + 6 H2O

In this reaction, ammonia (NH3) reacts with oxygen (O2) to form nitrogen dioxide (NO2) and water (H2O). The valence of nitrogen in the resulting oxide, nitrogen dioxide (NO2), is 2.

Calculation of the mass fraction of oxygen in the oxide:

To calculate the mass fraction of oxygen in the oxide, we need to know the molar masses of oxygen and the oxide. The molar mass of oxygen (O2) is approximately 32 g/mol.

Since the valence of nitrogen in the oxide is 2, the formula of the oxide can be written as NO2. The molar mass of nitrogen dioxide (NO2) is approximately 46 g/mol.

To calculate the mass fraction of oxygen in the oxide, we can use the following formula:

Mass fraction of oxygen = (Molar mass of oxygen / Molar mass of the oxide) * 100

Substituting the values, we get:

Mass fraction of oxygen = (32 g/mol / 46 g/mol) * 100 ≈ 69.6%

Therefore, the mass fraction of oxygen in the oxide is approximately 69.6%.

Please note that the values provided are approximate and may vary slightly depending on the specific conditions and experimental data.