Question

За поданим рівнянням реакції 2Mg + O2 + 2MgO; ДН = -1205 кДж обчисли, яка кількість теплоти виділиться внаслідок взаємодії магнію масою 96 г.

Answer 1

Удачи!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

Calculation of Heat Released in the Reaction

To calculate the amount of heat released in the reaction, we can use the equation:

q = m * ΔH

Where: - q is the heat released or absorbed in the reaction, - m is the mass of the substance involved in the reaction, and - ΔH is the enthalpy change of the reaction.

In this case, we have the reaction: 2Mg + O2 → 2MgO

The enthalpy change (ΔH) for this reaction is given as -1205 kJ/mol.

To calculate the heat released, we need to convert the mass of magnesium (96 g) to moles. The molar mass of magnesium (Mg) is 24.31 g/mol.

Let's calculate the number of moles of magnesium:

moles of Mg = mass of Mg / molar mass of Mg

moles of Mg = 96 g / 24.31 g/mol

moles of Mg = 3.95 mol

Now, we can calculate the heat released using the equation mentioned earlier:

q = m * ΔH

q = 3.95 mol * -1205 kJ/mol

q = -4754.75 kJ

Therefore, the amount of heat released in the reaction between 2 moles of magnesium and 1 mole of oxygen to form 2 moles of magnesium oxide is approximately -4754.75 kJ.