Question

Вставте пропущені коефіцієнти 1)...Fe(OH)3=...Fe2O3+...H2O 2)...KNO3=...KNO2+...O2 3)Cr2O3+...C=...Cr+...CO 4)...Fe+...CuSO4=...FeSO4+...Cu 5)FeCl2+...Cl2=...FeCl3 6)...Al(OH)3=...Al2O3+...H2O 7)...WO3+...H2=...W+H2O 8)Na+...H2O=NaOH+...H2 9)...Ca+...H2O=Ca(OH)2+...H2 10)...Ti(OH)4=...TiO2+...H2O 11)...Fe2O3+...H2=...Fe+...H2O 12)...ZnCl2+...Al=...AlCl3+Zn ПОМОГИТЕЕЕЕ даю 50 балов

Answer 1

Відповідь:

Окі

Пояснення:

1)2Fe(OH)3=Fe2O3+3H2O

2)2KNO3=2KNO2+O2

3)Cr2O3+3C=2Cr+3CO

4)Fe+CuSO4=FeSO4+Cu

5)2FeCl2+Cl2=2FeCl3

6)2Al(OH)3=Al2O3+3H2O

7)WO3+3H2=W+3H2O

8)2Na+2H2O=2NaOH+H2

9)Ca+2H2O=Ca(OH)2+H2

10)Ti(OH)4=TiO2+2H2O

11)Fe2O3+3H2=2Fe+3H2O

12)3ZnCl2+2Al=2AlCl3+3Zn

Answer 2

1) Fe(OH)3 = Fe2O3 + H2O - The balanced equation for this reaction is: 2Fe(OH)3 = Fe2O3 + 3H2O [[1]].

2) KNO3 = KNO2 + O2 - The balanced equation for this reaction is: 2KNO3 = 2KNO2 + O2 [[2]].

3) Cr2O3 + C = Cr + CO - The balanced equation for this reaction is: Cr2O3 + 3C = 2Cr + 3CO [[3]].

4) Fe + CuSO4 = FeSO4 + Cu - The balanced equation for this reaction is: Fe + CuSO4 = FeSO4 + Cu [[4]].

5) FeCl2 + Cl2 = FeCl3 - The balanced equation for this reaction is: 2FeCl2 + Cl2 = 2FeCl3 [[5]].

6) Al(OH)3 = Al2O3 + H2O - The balanced equation for this reaction is: 2Al(OH)3 = Al2O3 + 3H2O [[6]].

7) WO3 + H2 = W + H2O - The balanced equation for this reaction is: WO3 + 3H2 = 2W + 3H2O [[7]].

8) Na + H2O = NaOH + H2 - The balanced equation for this reaction is: 2Na + 2H2O = 2NaOH + H2 [[8]].

9) Ca + H2O = Ca(OH)2 + H2 - The balanced equation for this reaction is: Ca + 2H2O = Ca(OH)2 + H2 [[9]].

10) Ti(OH)4 = TiO2 + H2O - The balanced equation for this reaction is: Ti(OH)4 = TiO2 + 2H2O [[10]].

11) Fe2O3 + H2 = Fe + H2O - The balanced equation for this reaction is: Fe2O3 + 3H2 = 2Fe + 3H2O [[11]].

12) ZnCl2 + Al = AlCl3 + Zn - The balanced equation for this reaction is: 2ZnCl2 + 2Al = 2AlCl3 + 2Zn [[12]].

I hope this helps! Let me know if you have any further questions.