Question

4. Составьте словесные уравнения реакций фосфора (V) и железа (II|) с кислородом и подчеркните продукты - оксиды. Определите характер образующихся оксидов,​

Answer 1

1. Фосфор + кислород ⇒ оксид фосфора (Ⅴ).

Уравнение химической реакции : $\sf 4P + 5O_2 \to 2\underline{P_2O_5}$.

Полученный оксид – оксид фосфора (Ⅴ) – P₂O₅ имеет кислотный характер.

2. Железо + кислород ⇒ оксид железа (Ⅲ).

Уравнение химической реакции : $\sf 4Fe + 3O_2 \to 2\underline{Fe_2O_3}$.

Полученный оксид – оксид железа (Ⅲ) – Fe₂O₃ имеет амфотерный характер (в зависимости от условий может проявлять оснóвные или кислотные свойства).

Answer 2

Word Equations for the Reaction of Phosphorus (V) and Iron (II) with Oxygen

The word equations for the reaction of phosphorus (V) and iron (II) with oxygen can be written as follows:

1. Phosphorus (V) with Oxygen: - Phosphorus pentoxide is formed when phosphorus (V) reacts with oxygen.

The word equation for this reaction is: - Phosphorus (V) + Oxygen → Phosphorus pentoxide

2. Iron (II) with Oxygen: - Iron (II) oxide is formed when iron (II) reacts with oxygen.

The word equation for this reaction is: - Iron (II) + Oxygen → Iron (II) oxide

Character of the Formed Oxides

1. Phosphorus pentoxide: - Phosphorus pentoxide (P2O5) is an acidic oxide. It reacts with water to form phosphoric acid, which is a strong acid.

2. Iron (II) oxide: - Iron (II) oxide (FeO) is a basic oxide. It can react with acids to form salts and water.

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