Question

3.( 5 балла) Закончите уравнения реакций. Расставьте коэффициенты. a) Cl + Oz - СЬО- b) KCIO; → КС1 + О2 c) Fe+ H2SO4 - Fe:(SO4)3 + H2 H₂SO4 d) Cu(OH)₂ CuO + H₂O

Answer 1

Ответ:a) Cl + O2 → Cl2O7 (это озон)

b) 2KClO3 → 2KCl + 3O2 (это разложение хлората калия)

c) 3Fe + 3H2SO4 → 3Fe2(SO4)3 + 3H2 (это реакция железа с серной кислотой, образующая сульфат железа(III) и водород)

d) Cu(OH)2 → CuO + H2O (это разложение гидроксида меди(II) на оксид меди(II) и воду)

Теперь уравнения сбалансированы, их коэффициенты указаны так, чтобы количество атомов каждого элемента слева и справа от реакции было одинаковым.

Объяснение:

Answer 2

a) Cl2 + O2 -> ClO2 To balance the equation, we need to make sure that the number of atoms on both sides of the equation is equal. In this case, we have 2 chlorine atoms on the left side and 1 chlorine atom on the right side. To balance the chlorine atoms, we can put a coefficient of 2 in front of ClO2:

2 Cl2 + O2 -> 2 ClO2

Now let's check the oxygen atoms. On the left side, we have 2 oxygen atoms from Cl2 and 2 oxygen atoms from O2, giving us a total of 4 oxygen atoms. On the right side, we have 4 oxygen atoms from 2 ClO2 molecules. The equation is now balanced.

b) KClO3 -> KCl + O2 The equation is already balanced. There is 1 potassium atom, 1 chlorine atom, and 3 oxygen atoms on both sides of the equation.

c) Fe + H2SO4 -> Fe2(SO4)3 + H2 To balance this equation, we'll start by balancing the iron (Fe) atoms. On the left side, we have 1 Fe atom, and on the right side, we have 2 Fe atoms in Fe2(SO4)3. So we'll put a coefficient of 2 in front of Fe on the left side:

2 Fe + H2SO4 -> Fe2(SO4)3 + H2

Now let's balance the sulfur (S) atoms. On the left side, we have 1 S atom from H2SO4, and on the right side, we have 3 S atoms in Fe2(SO4)3. To balance the S atoms, we'll put a coefficient of 3 in front of H2SO4:

2 Fe + 3 H2SO4 -> Fe2(SO4)3 + H2

Finally, let's balance the hydrogen (H) atoms. On the left side, we have 6 H atoms from 3 H2SO4 molecules, and on the right side, we have 6 H atoms in 3 H2 molecules. The equation is now balanced.

d) Cu(OH)2 -> CuO + H2O To balance this equation, we'll start by balancing the copper (Cu) atoms. On the left side, we have 1 Cu atom, and on the right side, we have 1 Cu atom in CuO. So the Cu atoms are already balanced.

Next, let's balance the oxygen (O) atoms. On the left side, we have 2 O atoms from Cu(OH)2, and on the right side, we have 1 O atom in CuO. To balance the O atoms, we'll put a coefficient of 2 in front of CuO:

Cu(OH)2 -> 2 CuO + H2O

Finally, let's balance the hydrogen (H) atoms. On the left side, we have 4 H atoms from 2 Cu(OH)2 molecules, and on the right side, we have 2 H atoms in 1 H2O molecule. To balance the H atoms, we'll put a coefficient of 4 in front of H2O:

Cu(OH)2 -> 2 CuO + 4 H2O

The equation is now balanced.