Question

ДАЮ МАКСИМАЛЬНЫЙ БАЛЛ!!! СРОЧНО!!!!! 1. Рассчитать валентности элементов по формулам 1) CBr4 N2O HF PH3 SiO2 Al2S3 Mg3P2 2) CaO H2S Cr2O3 SBr4 Na3N Cu2O AlF3 3) Al4C3 PCl5 SiO2 Cl2O5 CaBr2 Li3N CO 2. Расставьте коэффициенты в следующих уравнениях реакций. Определите типы реакций: 1. СаСО3 ® СаО + CO2 2. Na2SO4 + ВаСl2 ® NaСl + ВаSO4 3. SO3 + H2O ® H2SO4 4. Cu(OH)2 + HNO3 ® Cu(NO3)2 + H2O 5. Fe(OH)3 ® Fe2O3 + H2O 6. Аl2(SO4)3 + NaOH ® Na2SO4 + Аl(OH)3¯

Answer 1

Ответ:

1) CBr4(C=4, Br=1) Na2O(Na=1,O=2) HF(H=1,F=1) PH3(P=3,H=1), SiO2(Si=4,O=2), Al2S3(Al=3,S=2), Mg3P2(Mg=2, P=3).

2)CaO (Ca=2,O=2), H2S(H=1,S=2), Cr2O3(Cr=3,O=2), SBr4(S=4,Br=1), Na3N(Na=1, N=3), Cu2O (Cu=1, O=2), AlF3(Al=3,F=1)

3) Al4C3 (C=4, Al=3), PCl5(P=5,Cl=1), SiO2(Si=4,O=2), Cl2O5(Cl=5, O=2), CaBr2(Ca=2,Br=1), Li3N(Li=1,N=3), CO(C=2,O=2)

2. 1) CaCO3=CaO+CO2 — реакция разложения

2) Na2SO4+BaCl2=BaSO4+2NaCl — реакция обмена

3) SO3+H2O=H2SO4 — реакция соединения

4) Cu(OH)2+2HNO3=2Cu(NO3)2+2H2O — реакция нейтрализации

5) 2Fe(OH)3=Fe2O3+3H2O — реакция разложения

6)Al2(SO4)3+6NaOH=3Na2SO4+2Al(OH)3 — реакция обмена

Answer 2

Valence of Elements:

1) The valence of the elements can be determined by looking at their electron configuration and the number of valence electrons they have. Here are the valences of the elements mentioned:

- CBr4: Carbon (C) has a valence of 4, Bromine (Br) has a valence of 1. - N2O: Nitrogen (N) has a valence of 3, Oxygen (O) has a valence of 2. - HF: Hydrogen (H) has a valence of 1, Fluorine (F) has a valence of 1. - PH3: Phosphorus (P) has a valence of 3, Hydrogen (H) has a valence of 1. - SiO2: Silicon (Si) has a valence of 4, Oxygen (O) has a valence of 2. - Al2S3: Aluminum (Al) has a valence of 3, Sulfur (S) has a valence of 2. - Mg3P2: Magnesium (Mg) has a valence of 2, Phosphorus (P) has a valence of 3.

2) - CaO: Calcium (Ca) has a valence of 2, Oxygen (O) has a valence of 2. - H2S: Hydrogen (H) has a valence of 1, Sulfur (S) has a valence of 2. - Cr2O3: Chromium (Cr) has a valence of 3, Oxygen (O) has a valence of 2. - SBr4: Sulfur (S) has a valence of 2, Bromine (Br) has a valence of 1. - Na3N: Sodium (Na) has a valence of 1, Nitrogen (N) has a valence of 3. - Cu2O: Copper (Cu) has a valence of 2, Oxygen (O) has a valence of 2. - AlF3: Aluminum (Al) has a valence of 3, Fluorine (F) has a valence of 1.

3) - Al4C3: Aluminum (Al) has a valence of 3, Carbon (C) has a valence of 4. - PCl5: Phosphorus (P) has a valence of 5, Chlorine (Cl) has a valence of 1. - SiO2: Silicon (Si) has a valence of 4, Oxygen (O) has a valence of 2. - Cl2O5: Chlorine (Cl) has a valence of 1, Oxygen (O) has a valence of 2. - CaBr2: Calcium (Ca) has a valence of 2, Bromine (Br) has a valence of 1. - Li3N: Lithium (Li) has a valence of 1, Nitrogen (N) has a valence of 3. - CO: Carbon (C) has a valence of 4, Oxygen (O) has a valence of 2.

Balancing Chemical Equations:

1) CaCO3 -> CaO + CO2 - This is a decomposition reaction.

2) Na2SO4 + BaCl2 -> 2NaCl + BaSO4 - This is a double displacement reaction.

3) SO3 + H2O -> H2SO4 - This is a synthesis reaction.

4) Cu(OH)2 + 2HNO3 -> Cu(NO3)2 + 2H2O - This is a double displacement reaction.

5) Fe(OH)3 -> Fe2O3 + 3H2O - This is a decomposition reaction.

6) Al2(SO4)3 + 6NaOH -> 3Na2SO4 + 2Al(OH)3 - This is a double displacement reaction.

Please note that the coefficients in the balanced equations are not provided as they require a more detailed calculation.