Question

H2+Br2>HBrРозтавити кофіцієнти ​

Answer 1

Ответ:

Объяснение:

H2+Br2 = 2HBr

Answer 2

The reaction H2 + Br2 → 2HBr represents the reaction between hydrogen and bromine to produce hydrogen bromide. This reaction occurs through a radical mechanism, which means that it involves highly reactive species with one or more unpaired electrons .

The individual steps of the reaction can be written as follows:

1. Br2 → Br + Br (a) 2. Br+H2 → H+HBr (b) 3. H + Br2 → Br+ HBr (c) 4. H + HBr → H2 + Br (d) 5. Br + Br + M → Br2 + M (a)

Where (a), (b), (c), and (d) are the rates of the corresponding steps, and M represents the solvent.

The rate of formation of HBr is given by the expression:

2kb(ka/ko)' 1/2 [H2] [Br2]^3/2 /{[Br2] + (kd/ko)}

Where: - kb, ka, kd, and ko are the rates of the corresponding steps, - [H2] and [Br2] are the concentrations of hydrogen and bromine, respectively.

This expression shows that the rate of formation of HBr depends on the concentrations of hydrogen and bromine, as well as the rates of the individual steps .

As for the percent composition by volume of the reaction, it is calculated by dividing the number of moles of each reactant by the total number of moles in the reaction, and then multiplying by 100 to get a percentage. For example, if the reaction H2 + Br2 → 2HBr produces 2 moles of HBr from 1 mole of H2 and 1 mole of Br2, the percent composition by volume would be:

- HBr: (2 moles / 3 moles) * 100 = 66.67% - H2: (1 mole / 3 moles) * 100 = 33.33% - Br2: (1 mole / 3 moles) * 100 = 33.33%

This means that for every 100 volumes of the reaction, 66.67 volumes are HBr, 33.33 volumes are H2, and 33.33 volumes are Br2 .